In June, 2009 , Harris Interactive conducted its Great Schools Survey. In this
survey, the sample consisted of 1,086 adults who were parents of school-aged
children. The sample was selected to be representative of the population of
parents of school-aged children. One question on the survey asked respondents
how much time per month (in hours) they spent volunteering at their children's
school during the previous school year. The following summary statistics for
time volunteered per month were given:
\(n=1086 \quad \bar{x}=5.6 \quad\) median \(=1\)
a. What does the fact that the mean is so much larger than the median tell you
about the distribution of time spent volunteering at school per month?
b. Based on your answer to Part (a), explain why it is not reasonable to
assume that the population distribution of time spent volunteering is
approximately normal.
c. Explain why it is appropriate to use the one-sample \(t\) confidence interval
to estimate the mean time spent volunteering for the population of parents of
school-aged children even though the population distribution is not
approximately normal.
d. Suppose that the sample standard deviation was \(s=5.2\). Use the five-step
process for estimation problems \(\left(\mathrm{EMC}^{3}\right)\) to calculate
and interpret a \(98 \%\) confidence interval for \(\mu,\) the mean time spent
volunteering for the population of parents of school-aged children. (Hint: See
Example 12.7)