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The report referenced in the previous exercise also stated that the proportion who thought their parents would help with buying a house or renting an apartment for the sample of young adults was 0.37 . For the sample of parents, the proportion who said they would help with buying a house or renting an apartment was 0.27 . Based on these data, can you conclude that the proportion of parents who say they would help with buying a house or renting an apartment is significantly less than the proportion of young adults who think that their parents would help?

Short Answer

Expert verified
Depending on the calculated p-value, we either reject or fail to reject the null hypothesis. If the p-value is less than 0.05, then we reject the null hypothesis and conclude that there is a significant difference between the proportion of young adults who think their parents would help versus the proportion of parents who say they would help. If the p-value is greater than 0.05, then we fail to reject the null hypothesis and conclude that there is not a significant difference.

Step by step solution

01

Calculating the Pooled Proportion

The pooled proportion is the total 'successes' divided by the total sample size. Here, a 'success' means help was provided. Suppose that each sample has a size of n. Then, the pooled proportion, p, can be calculated like this: p = [p1*n + p2*n] / [2*n]. Using the given proportions 0.37 (p1) and 0.27 (p2), we get p = (0.37n + 0.27n) / (2n) = 0.32.
02

Computing the Test Statistic (Z Score)

The test statistic for a hypothesis test for two proportions is a Z-score. The formula for the test statistic is Z = (p1 - p2) / sqrt [p(1-p){(1/n1)+(1/n2)}]. Using 0.37 as p1, 0.27 as p2, 0.32 for p, and assuming sample sizes n1 = n2 = n, we substitute these values into the formula to get Z.
03

Finding the P-Value

Once we have the Z score, we determine the p-value. The p-value is the probability that a variable would be observed as extreme as the test statistic assuming the null hypothesis is true. If the p-value is smaller than the significance level (usually 0.05), then we reject the null hypothesis. In our case, we look up the P(Z > obtained z score) in a standard normal (Z) distribution table.
04

Making the Decision

After obtaining the p-value, we compare it to our significance level (commonly 0.05). If the p-value is smaller than 0.05, we reject the null hypothesis and conclude that there is a significant difference between two populations.

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Most popular questions from this chapter

Reported that the percentage of U.S. residents living in poverty was \(12.5 \%\) for men and \(15.1 \%\) for women. These percentages were estimates based on data from large representative samples of men and women. Suppose that the sample sizes were 1,200 for men and 1,000 for women. You would like to use the survey data to estimate the difference in the proportion living in poverty for men and women. (Hint: See Example 11.2) a. Answer the four key questions (QSTN) for this problem. What method would you consider based on the answers to these questions? b. Use the five-step process for estimation problems \(\left(\mathrm{EMC}^{3}\right)\) to calculate and interpret a \(90 \%\) large- sample confidence interval for the difference in the proportion living in poverty for men and women.

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