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Let \(p\) denote the proportion of students living on campus at a large university who plan to move off campus in the next academic year. For a large sample \(z\) test of \(H_{0}: p=0.70\) versus \(H_{\mathrm{a}}: p>0.70,\) find the \(P\) -value associated with each of the following values of the \(z\) test statistic. a. 1.40 b. 0.92 c. 1.85 d. 2.18 e. -1.40

Short Answer

Expert verified
The P-values for the given z-test statistics can be found with the use of a standard normal distribution table or statistical software. If the calculated P-value is less than the significance level (0.05 is commonly used), it provides strong evidence against the null hypothesis that the proportion of students who plan to move off campus the next year is 0.70.

Step by step solution

01

Understand the problem and identify P-value

The problem is asking to find the P-value for each given z test statistic. P-values are obtained by integrating the standard normal curve from the value of the z score to infinity because the test is right-tailed (i.e., \(H_{a}: p>0.70\)). The aim is to find the area under the curve for the given values of z.
02

Calculation of P-value for each z-value

The P-value is calculated by looking up the z-scores in a table of the standard normal distribution, or using a function such as norm.sf(z-score) in a statistical software or programming language that incorporates statistical functions, and then subtracting the result from 1 if necessary to get a right-tail probability. Repeat this process for each of the given z-values: 1.40, 0.92, 1.85, 2.18, and -1.40.
03

Interpret the results

The calculated P-values represent the probability of obtaining a z-score as extreme as the one observed given that the null hypothesis is true. The smallest the P-value, the strongest is the evidence against the null hypothesis in favor of the alternative. Compare the calculated P-values with the significance level (usually 0.05). If the P-value is smaller than the significance level, you would reject the null hypothesis.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Hypothesis Testing
Hypothesis testing is a statistical method used to determine whether there is enough evidence in a sample of data to infer that a certain condition holds true for the entire population. The process begins by proposing two opposing hypotheses: the null hypothesis (\(H_{0}\)) and the alternative hypothesis (\(H_{a}\)). The null hypothesis typically represents a baseline or status quo condition, while the alternative hypothesis represents what the researcher is trying to provide evidence for. Hypothesis testing then uses sample data to decide whether to reject the null hypothesis in favor of the alternative, based on a calculated probability value, or P-value.

By setting a significance level, typically 0.05, researchers have a cutoff for deciding whether to reject the null hypothesis. If the P-value is lower than the significance level, it suggests that the observed data is highly unlikely under the assumption that the null hypothesis is true, supporting the alternative hypothesis.
Standard Normal Distribution
The standard normal distribution is a special case of the normal distribution that has a mean of zero and a standard deviation of one. This distribution is symmetrical around the mean, and it has a bell-shaped curve, reflecting how random variables are expected to be distributed in many natural and social phenomena. When dealing with hypothesis testing and P-values, the z test statistic, derived from our sample data, is often compared against this standard normal distribution.

Since it's standardized, it allows us to transform scores from a normal distribution into a comparable form called z-scores. Z-scores indicate how many standard deviations an element is from the mean and can be used to calculate probabilities and P-values for hypothesis tests.
Statistical Significance
In hypothesis testing, statistical significance is determined by the P-value, which measures the strength of the evidence against the null hypothesis. If the P-value is low, the test results are statistically significant, meaning the difference found in the data is unlikely to be due to chance alone. A common threshold for statistical significance is a P-value of less than 0.05, which means there is less than a 5% probability that the observed results are a consequence of random variation.
Null Hypothesis
The null hypothesis, denoted as \(H_{0}\), constitutes the default statement that there is no effect or no difference, and any observed effect is due to sampling or experimental error. For example, in the provided exercise, the null hypothesis claims that the proportion of students living on campus who plan to move off campus is 70%, represented as \(H_{0}: p=0.70\). When conducting a z test, the null hypothesis becomes a benchmark to determine if the data provides enough evidence to support the alternative hypothesis.
Alternative Hypothesis
Opposing the null hypothesis is the alternative hypothesis, represented as \(H_{a}\) or \(H_{1}\), which asserts that there is a statistically significant effect or difference that the research aims to detect. In the context of our exercise, the alternative hypothesis suggests that more than 70% of students plan to leave campus housing, written as \(H_{a}: p>0.70\). If the P-value obtained from the z test is low enough, it supports the alternative hypothesis, suggesting a movement of the student proportion beyond the 70% indicated by the null hypothesis.
Normal Distribution Tables
To find the P-value from a z test statistic, one can use normal distribution tables, also known as z-tables. These tables provide the cumulative probability associated with a given z-score, which typically represents the area under the curve to the left of that z-score on the standard normal distribution. For the right-tailed test in our exercise (where \(H_{a}: p>0.70\)), the P-value can be found by subtracting the table value from 1. Since z-tables are based on a standardized distribution, they provide a convenient way to translate z-scores into probabilities without doing complex calculations.

It's important to note that the P-value is not the absolute probability of the null hypothesis being true or false but rather measures the probability of obtaining a result at least as extreme as the one observed, given that the null hypothesis is true.

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Most popular questions from this chapter

USA Today (March 4, 2010) described a survey of 1,000 women ages 22 to 35 who work full time. Each woman who participated in the survey was asked if she would be willing to give up some personal time in order to make more money. To determine if the resulting data provided convincing evidence that the majority of women ages 22 to 35 who work full time would be willing to give up some personal time for more money, what hypotheses should you test?

Every year on Groundhog Day (February 2), the famous groundhog Punxsutawney Phil tries to predict whether there will be 6 more weeks of winter. The article "Groundhog Has Been Off Target" (USA Today, Feb. 1,2011 ) states that "based on weather data, there is no predictive skill for the groundhog." Suppose that you plan to take a random sample of 20 years and use weather data to determine the proportion of these years the groundhog's prediction was correct. a. Describe the shape, center, and spread of the sampling distribution of \(\hat{p}\) for samples of size 20 if the groundhog has only a \(50-50\) chance of making a correct prediction. b. Based on your answer to Part (a), what sample proportion values would convince you that the groundhog's predictions have a better than \(50-50\) chance of being correct?

Let \(p\) denote the proportion of students at a large university who plan to purchase a campus meal plan in the next academic year. For a large-sample \(z\) test of \(H_{0}: p=0.20\) versus \(H: p<0.20,\) find the \(P\) -value associated with each of the following values of the \(z\) test statistic. (Hint: See pages \(442-443)\) a. -0.55 b. -0.92 c. -1.99 d. -2.24 e. 1.40

Use the definition of the \(P\) -value to explain the following: a. Why \(H_{0}\) would be rejected if \(P\) -value \(=0.0003\) b. Why \(H_{0}\) would not be rejected if \(P\) -value \(=0.350\)

Consider the following quote from the article "Review Finds No Link Between Vaccine and Autism" (San Luis Obispo Tribune, October 19,2005 ): "We found no evidence that giving MMR causes Crohn's disease and/or autism in the children that get the MMR,' said Tom Jefferson, one of the authors of The Cochrane Review. 'That does not mean it doesn't cause it. It means we could find no evidence of it." (MMR is a measles-mumps-rubella vaccine.) In the context of a hypothesis test with the null hypothesis being that MMR does not cause autism, explain why the author could not conclude that the MMR vaccine does not cause autism.

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