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Explain why you would not reject the null hypothesis if the \(P\) -value were 0.37 .

Short Answer

Expert verified
The null hypothesis would not be rejected because the P-value, 0.37, is greater than the commonly used significance level of 0.05. Therefore, there is insufficient evidence to reject the null hypothesis.

Step by step solution

01

Understanding the meaning of P-value

The P-value is a probability that provides a measure of the evidence against the null hypothesis provided by the data. Smaller P-values provide stronger evidence against the null hypothesis.
02

Understanding the significance level

The significance level, denoted by \(\alpha\), is a threshold below which the null hypothesis is rejected. It is often set at 0.05, which means that there is a 5% risk of wrongly rejecting the null hypothesis.
03

Comparing P-value with the significance level

Here, the P-value is given as 0.37, which is greater than the widely accepted significance level of 0.05.
04

Deciding whether to reject the null hypothesis

Since the P-value is greater than the significance level, we do not reject the null hypothesis.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Null Hypothesis
In the realm of hypothesis testing, the null hypothesis, denoted as H0, stands as the default assumption that no relationship exists between two measured phenomena. To illustrate, let's consider an educational study determining whether a new teaching method improves student test scores. The null hypothesis would assert that there is no difference in test scores between students taught by the standard method and those learning through the new method.

The critical role of the null hypothesis in research is to provide a baseline for testing statistical significance. We compare the observed data against the predictions of the null hypothesis. If the data significantly diverge from what the null hypothesis would expect, this could indicate that our alternate hypothesis, which suggests there is an effect or difference, might be true.

In the given exercise, not rejecting the null hypothesis when the P-value is 0.37 implies that the data does not provide strong enough evidence to conclude that the new teaching method has a different effect on test scores compared to the traditional method.
Significance Level
The significance level, denoted as \( \alpha \), is crucial in determining the threshold for what is considered statistically significant when conducting a hypothesis test. This pre-established criterion helps researchers avoid random fluctuations leading to incorrect rejection of the null hypothesis—an error known as Type I error. Commonly, a significance level of 0.05 is chosen, which translates to a 5% probability of rejecting the null hypothesis when it is actually true.

Understanding the Threshold

Think of the significance level like a cut-off point in a race; only times below it 'win,' which in statistics means we would only reject the null hypothesis when our P-value is lower than \( \alpha \). Thus, in our exercise, since the P-value of 0.37 is much higher than the standard significance level of 0.05, it doesn't 'beat' the cut-off mark, which is why we would not reject the null hypothesis.
Probability in Statistics
Probability is the backbone of statistics, portraying the chance that a particular event will occur. In hypothesis testing, probability helps us quantify how likely it is to obtain the observed data, or data more extreme, if the null hypothesis were true. The P-value conveys this probability and is a central figure in deciding whether to reject the null hypothesis.

Evaluating Evidence with Probability

When we obtain a P-value in an experiment or study, we essentially ask ‘What is the chance of seeing these results if the null hypothesis is correct?’ A high P-value suggests that the observed data are quite likely under the null hypothesis, indicating insufficient evidence to support the alternative hypothesis. Therefore, when our exercise presents a P-value of 0.37, this implies that there's a 37% probability the results could occur by random chance under the null hypothesis. It's a relatively large chance, which leads us to maintain our initial assumption (the null hypothesis) rather than reject it in favor of the alternative.

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Most popular questions from this chapter

The article "Most Customers OK with New Bulbs" (USA Today, Feb. 18,2011 ) describes a survey of 1,016 randomly selected adult Americans. Each person in the sample was asked if they have replaced standard light bulbs in their home with the more energy efficient compact fluorescent (CFL) bulbs. Suppose you want to use the survey data to determine if there is evidence that more than \(70 \%\) of adult Americans have replaced standard bulbs with CFL bulbs. Let \(p\) denote the proportion of all adult Americans who have replaced standard bulbs with CFL bulbs. a. Describe the shape, center, and spread of the sampling distribution of \(\hat{p}\) for random samples of size 1,016 if the null hypothesis \(H_{0}: p=0.70\) is true. b. Would you be surprised to observe a sample proportion as large as \(\hat{p}=0.72\) for a sample of size 1,016 if the null hypothesis \(H_{0}: p=0.70\) were true? Explain why or why not. c. Would you be surprised to observe a sample proportion as large as \(\hat{p}=0.75\) for a sample of size 1,016 if the null hypothesis \(H_{0}: p=0.70\) were true? Explain why or why not. d. The actual sample proportion observed in the study was \(\hat{p}=0.71\). Based on this sample proportion, is there convincing evidence that more than \(70 \%\) have replaced standard bulbs with CFL bulbs, or is this sample proportion consistent with what you would expect to see when the null hypothesis is true? Support your answer with a probability calculation.

Every year on Groundhog Day (February 2), the famous groundhog Punxsutawney Phil tries to predict whether there will be 6 more weeks of winter. The article "Groundhog Has Been Off Target" (USA Today, Feb. 1,2011 ) states that "based on weather data, there is no predictive skill for the groundhog." Suppose that you plan to take a random sample of 20 years and use weather data to determine the proportion of these years the groundhog's prediction was correct. a. Describe the shape, center, and spread of the sampling distribution of \(\hat{p}\) for samples of size 20 if the groundhog has only a \(50-50\) chance of making a correct prediction. b. Based on your answer to Part (a), what sample proportion values would convince you that the groundhog's predictions have a better than \(50-50\) chance of being correct?

Which of the following specify legitimate pairs of null and alternative hypotheses? a. \(H_{0}: p=0.25 \quad H_{a}: p>0.25\) b. \(H_{0}: p<0.40 \quad H_{a}: p>0.40\) c. \(H_{0}: p=0.40 \quad H_{a}: p<0.65\) d. \(H_{0}: p \neq 0.50 \quad H_{a}: p=0.50\) e. \(H_{0}: p=0.50 \quad H_{a}: p>0.50\) f. \(H_{0}: \hat{p}=0.25 \quad H: \hat{p}>0.25\)

Explain why the statement \(\hat{p}>0.50\) is not a legitimate hypothesis.

A college has decided to introduce the use of plus and minus with letter grades, as long as there is convincing evidence that more than \(60 \%\) of the faculty favor the change. A random sample of faculty will be selected, and the resulting data will be used to test the relevant hypotheses. If \(p\) represents the proportion of all faculty who favor a change to plus-minus grading, which of the following pairs of hypotheses should be tested? $$H_{0}: p=0.6 \text { versus } H_{a}: p<0.6$$ or $$H_{0}: p=0.6 \text { versus } H_{a}: p>0.6$$ Explain your choice.

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