Chapter 10: Problem 46
Explain why you would not reject the null hypothesis if the \(P\) -value were 0.37 .
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Chapter 10: Problem 46
Explain why you would not reject the null hypothesis if the \(P\) -value were 0.37 .
These are the key concepts you need to understand to accurately answer the question.
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Get started for freeThe article "Most Customers OK with New Bulbs" (USA Today, Feb. 18,2011 ) describes a survey of 1,016 randomly selected adult Americans. Each person in the sample was asked if they have replaced standard light bulbs in their home with the more energy efficient compact fluorescent (CFL) bulbs. Suppose you want to use the survey data to determine if there is evidence that more than \(70 \%\) of adult Americans have replaced standard bulbs with CFL bulbs. Let \(p\) denote the proportion of all adult Americans who have replaced standard bulbs with CFL bulbs. a. Describe the shape, center, and spread of the sampling distribution of \(\hat{p}\) for random samples of size 1,016 if the null hypothesis \(H_{0}: p=0.70\) is true. b. Would you be surprised to observe a sample proportion as large as \(\hat{p}=0.72\) for a sample of size 1,016 if the null hypothesis \(H_{0}: p=0.70\) were true? Explain why or why not. c. Would you be surprised to observe a sample proportion as large as \(\hat{p}=0.75\) for a sample of size 1,016 if the null hypothesis \(H_{0}: p=0.70\) were true? Explain why or why not. d. The actual sample proportion observed in the study was \(\hat{p}=0.71\). Based on this sample proportion, is there convincing evidence that more than \(70 \%\) have replaced standard bulbs with CFL bulbs, or is this sample proportion consistent with what you would expect to see when the null hypothesis is true? Support your answer with a probability calculation.
Every year on Groundhog Day (February 2), the famous groundhog Punxsutawney Phil tries to predict whether there will be 6 more weeks of winter. The article "Groundhog Has Been Off Target" (USA Today, Feb. 1,2011 ) states that "based on weather data, there is no predictive skill for the groundhog." Suppose that you plan to take a random sample of 20 years and use weather data to determine the proportion of these years the groundhog's prediction was correct. a. Describe the shape, center, and spread of the sampling distribution of \(\hat{p}\) for samples of size 20 if the groundhog has only a \(50-50\) chance of making a correct prediction. b. Based on your answer to Part (a), what sample proportion values would convince you that the groundhog's predictions have a better than \(50-50\) chance of being correct?
Which of the following specify legitimate pairs of null and alternative hypotheses? a. \(H_{0}: p=0.25 \quad H_{a}: p>0.25\) b. \(H_{0}: p<0.40 \quad H_{a}: p>0.40\) c. \(H_{0}: p=0.40 \quad H_{a}: p<0.65\) d. \(H_{0}: p \neq 0.50 \quad H_{a}: p=0.50\) e. \(H_{0}: p=0.50 \quad H_{a}: p>0.50\) f. \(H_{0}: \hat{p}=0.25 \quad H: \hat{p}>0.25\)
Explain why the statement \(\hat{p}>0.50\) is not a legitimate hypothesis.
A college has decided to introduce the use of plus and minus with letter grades, as long as there is convincing evidence that more than \(60 \%\) of the faculty favor the change. A random sample of faculty will be selected, and the resulting data will be used to test the relevant hypotheses. If \(p\) represents the proportion of all faculty who favor a change to plus-minus grading, which of the following pairs of hypotheses should be tested? $$H_{0}: p=0.6 \text { versus } H_{a}: p<0.6$$ or $$H_{0}: p=0.6 \text { versus } H_{a}: p>0.6$$ Explain your choice.
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