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If x is a binomial random variable, calculate , , and for each of the following:

  1. n = 25, p = .5
  2. n = 80, p = .2
  3. n = 100, p = .6
  4. n = 70, p = .9
  5. n = 60, p = .8
  6. n = 1000, p = .04

Short Answer

Expert verified
  1. μ=12.5, σ2=6.25, andσ =2.5.
  2. μ=16, σ2=12.8, and σ=3.58.
  3. μ=60,σ2=24, and σ=4.9.
  4. μ=63,σ2=6.3, and σ=7.94.
  5. μ=48,σ2=9.6, and σ=3.1.
  6. μ=40, σ2=38.4, andσ =6.2.

Step by step solution

01

Computation of  μ

a. The product of the value of n (number of trials), which is 25, and the value of p (number of successes), which is 0.5, will give the value of the meanμ:

μ=np=25×0.5=12.5

The computed value of μis 12.5.

02

Computation of  σ2

The product of the value of n, which is 25, the value of p, which is 0.5, and the value of q, which is 0.5, will give the value of the variance σ2:

σ2=npq=np1-p=25×0.51-0.5=25×0.5×0.5=6.25

The computed value of σ2 is 6.25.

03

Computation of  σ

The square root of the value ofσ2, which is 6.25, will give the value of the standard deviationσ:

role="math" localid="1655710063873" σ=σ2=6.25=2.5

The computed value ofσis 2.5.

04

Computation of  μ

b. The product of the value of n, which is 80, and the value of p, which is 0.2, will give the value of μ:

μ=np=80×0.2=16

The computed value of μis 16.

05

Computation of  σ2

The product of the value of n, which is 80, the value of p, which is 0.2, and the value of q, which is 0.8, will give the value of σ2:

σ2=npq=np1-p=80×0.21-0.2=80×0.2×0.8=12.8

Thus, the computed value ofσ2is 12.8.

06

Computation of  σ

The square root of the value of σ2 , which is 6.25, will give the value of σ:

σ=σ2=12.8=3.58

The computed value of σis 3.58.

07

Computation of  μ

c. The product of the value of n, which is 100, and the value of p, which is 0.6, will give the value of μ:

μ=np=100×0.6=60

The computed value ofμis 60.

08

Computation of  σ2

The product of the value of n, which is 100, the value of p, which is 0.6, and the value of q, which is 0.4, will give the value of σ2:

σ2=npq=np1-p=100×0.61-0.6=100×0.6×0.4=24

Thus, the computed value of σ2is 24.

09

Computation of  σ

The square root of the value of σ2, which is 24, will give the value of σ:

σ=σ2=24=4.9

The computed value ofσis 4.9.

10

Computation of  

d. The product of the value of n, which is 70, and the value of p, which is 0.9, will give the value of μ:

role="math" localid="1655707768889" μ=np=70×0.9=63

The computed value ofμ is 63.

11

Computation of  

The product of the value of n, which is 70, the value of p, which is 0.9, and the value of q, which is 0.1, will give the value of σ2:

σ2=npq=np1-p=70×0.91-0.9=70×0.9×0.1=6.3

The computed value of σ2is 6.3

12

Computation of  σ

The square root of the value of σ2, which is 6.3, will give the value of σ:

σ=σ2=63=7.94

The computed value ofσ is 7.94.

13

Computation of  μ

e. The product of the value of n, which is 48, and the value of p, which is 0.8, will give the value of μ:

μ=np=60×0.8=48

The computed value ofμis 48.

14

Computation of  σ2

The product of the value of n, which is 48, the value of p, which is 0.8, and the value of q, which is 0.2, will give the value of σ2:

σ2=npq=np(1-p)=60×0.81-0.8=60×0.8×0.2=9.6

The computed value ofσ2is 9.6.

15

Computation of  σ

The square root of the value of σ2, which is 9.6, will give the value of σ:

σ=σ2=9.6=3.1

The computed value ofσ is 3.1.

16

Computation of  μ

The product of the value of n, which is 1000, and the value of p, which is 0.04, will give the value of μ:

μ=np=1000×0.04=40

The computed value of μ is 40.

17

Computation of  σ2

The product of the value of n, which is 1000, the value of p, which is 0.04, and the value of q, which is 0.96, will give the value of σ2:

σ2=npq=np(1-p)=1000×0.041-0.04=1000×0.04×0.96=38.4

The computed value of σ2is 38.4.

18

Computation of  σ 

The square root of the value of σ2, which is 38.4, will give the value of σ:

role="math" localid="1655702205065" σ=σ2=38.4=6.2

The computed value of σis 6.2.

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