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A number between 1 and 10, inclusive, is randomly chosen, and the events A and B are defined as follows:

A: [The number is even.]

B: [The number is less than 7.]

a. Identify the sample points in the event AB.

b. Identify the sample points in the event AB.

c. Which expression represents the event that the number is even or less than 7 or both?

d. Which expression represents the event that the number is both even and less than 7?

Short Answer

Expert verified
  1. AB=[1,2,3,4,5,6]
  2. AB=[2,4,6]
  3. AB
  4. AB

Step by step solution

01

Determine the sample points in the event

A sample point is one of the experiment's possible outcomes in a probabilistic experiment. Sample space refers to the collection of all sample points.

So, a number between 1 and 10 is:

[1, 2, 3, 4, 5, 6, 7, 8, 9, 10]

Here,

A: [The number is even]

Equivalently,

A: [2, 4, 6, 8, 10]

B: [The number less than 7]

Equivalently,

B: [1, 2, 3, 4, 5, 6]

Union of sets A and B AB:

It identifies a set that occurs in either set A or B or both sets. We can observe that elements 1, 2, 3, 4, 5, and 6 occur in either set A or B.

Therefore, AB=[1,2,3,4,5,6]

02

Determine the sample points in the event

Intersect of set A and B, AB

It identifies a set that is common in set A and set B. We can observe that elements 1, 2, 3, 4, 5, and 6 are common in sets A and B.

Therefore, AB=[2,4,6]

Hence,2, 4, 6 are the sample points.

03

Identify the expression which represents the event that the number is even or less than 7 or both

The event which represents the number is even, less than 7, or both are:

AB=[1,2,3,4,5,6]

Because this includes even, less than 7, or both the numbers, hence,ABrepresents the expression.

04

Identify the expression which represents the event that the number is both even and less than 7

The event which represents the number is both even and less than seven is:

AB=[2,4,6]

Because this includes both even and less than seven numbers,

Hence, ABrepresents the expression.

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Most popular questions from this chapter

Shopping with a smartphone.Each year, United Parcel Service (UPS) commissions a “Pulse of the Online Shopper” survey. The 2015 survey included a sample of 5,118 U.S. shoppers who have made at least two online purchases

every three months. The survey revealed that 41% of the shoppers used a smartphone to make a purchase. Of those who made a smartphone purchase, 38% indicated that they preferred the mobile Web site to the full Web site accessed through a computer. Assume these percentages represent actual probabilities for the population of online shoppers. What is the probability that a randomly selected online shopper uses a smartphone to make a purchase and

prefers the mobile Web site?

Consider the Venn diagram below, were

P(E1)=P(E2)=P(E3)=15,P(E4)=P(E5)=120P(E6)=110,andP(E7)=15

Find each of the following probabilities:

a.P(A)b.P(B)c.P(AB)d.P(AB) e.P(Ac)f.P(Bc)g.P(AAc)h.P(AcB)

For two events, A and B, P(A)= .4, P(B)= .2 , and P(AB) = .1:

a. Find P (A/B).

b. Find P(B/A).

c. Are A and B independent events?

Male nannies. In a survey conducted by the International Nanny Association (INA) and reported on the INA Web site (www.nanny.org), 4,176 nannies were placed in a job in a given year. Only 24 of the nannies placed were men. Find the probability that a randomly selected nanny placed during the last year is a male nanny (a “mannie”).

Consider the experiment depicted by the Venn diagram, with the sample space S containing five sample points. The sample points are assigned the following probabilities:

P (E1) = .20, P (E2) = .30, P (E3)= .30, P (E4) = .10, P (E5) = .10.

a. Calculate P (A), P (B), and P (AB).

b. Suppose we know that event A has occurred, so that the reduced sample space consists of the three sample points in A—namely, E1, E2, and E3. Use the formula for conditional probability to adjust the probabilities of these three sample points for the knowledge that A has occurred [i.e., P (Ei/A)]. Verify that the conditional probabilities are in the same proportion to one another as the original sample point probabilities.

c. Calculate the conditional probabilityP (E1/A)in two ways: (1) Add the adjusted (conditional) probabilities of the sample points in the intersection AB, as these represent the event that B occurs given that A has occurred; (2) use the formula for conditional probability:

P (B/A) =P (AB)P (A)

Verify that the two methods yield the same result.

d. Are events A and B independent? Why or why not?

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