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Question: Tilting in online poker. In poker, making bad decisions due to negative emotions is known as tilting. A study in the Journal of Gambling Studies (March, 2014) investigated the factors that affect the severity of tilting for online poker players. A survey of 214 online poker players produced data on the dependent variable, severity of tilting (y), measured on a 30-point scale (where higher values indicate a higher severity of tilting). Two independent variables measured were poker experience (x1, measured on a 30-point scale) and perceived effect of experience on tilting (x2, measured on a 28-point scale). The researchers fit the interaction model, . The results are shown below (p-values in parentheses).

  1. Evaluate the overall adequacy of the model using α = .01.

b. The researchers hypothesize that the rate of change of severity of tilting (y) with perceived effect of experience on tilting (x2) depends on poker experience (x1). Do you agree? Test using α = .01.

Short Answer

Expert verified

Answer

  1. At 95% confidence interval, it can be concluded that at least one of the parametersβ1,β2,orβ3isnonzero.

b, At 95% confidence interval it is concluded that β3=0 Hence it can be concluded with enough evidence that x1and x2do not interact in the model.

Step by step solution

01

Overall adequacy of the model

To test the overall adequacy of the model, F-test is conducted

H0:β1=β2=β3=0Ha:Atleastoneoftheparametersβ1,β2,orβ3isnonzero

Here, F test statistic = SSEn-k+1=31.98

Value of F0.05,213,213 is 2.605

H0is rejected if F static >F0.05,213,213 for α=0.05,Since F >F0.05,213,213

Sufficient evidence to reject H0at 95% confidence interval

Thus,atleastoneoftheparametersβ1,β2,orβ3isnonzero

02

 Step 2: Overall adequacy of the model

H0:β3=0H0:β30

Here, t-test statistic = β^ssβ^s=-5.61

Value oft0.05,213 is 1.96

H0is rejected if t static > t0.05,24,24 .α=0.05 since t < t0.05,24,24

Not sufficient evidence to reject H0at 95% confidence interval

Therefore, β3=0

Hence it can be concluded with enough evidence that x1 and x2 donot interact in the model

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