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Question: Find the following probabilities for the standard normal random variable z:

a.P(z>1.46)b.P(z<-1.56)c.P(.67z<2.41)d.P(-1.96z-.33)e.P(Z0)f.P(-2.33<z<1.50)

Short Answer

Expert verified

Answer

A random variable is a mathematical expression of a statistical study's result.

Step by step solution

01

(a) The data is given below

The calculation is given below:

P(z>1.46)=1-P(z1.46)=1-0.9279=0.0721

02

(b) The data is given below

The calculation is given below:

P(z<-1.56)=0.0594

03

(c) The data is given below

The calculation is given below:


P(.67z<2.41)=P(.67z<2.41)-P(z<.0.67)=0.99920-0.7486=0.2434

04

(d) The data is given below

The calculation is given below:

P(-1.96z-.33)=P(-1.96Z<0)-P(-0.33Z<0)=0.4750-0.1293=0.3457

05

(e) The data is given below

The calculation is given below:

P(Z0)=1-P(z<0)=1-0.5=.5

06

(f) The data is given below

The calculation is given below:

P(-2.33<z<1.50)=P(-2.33<z<0)+P(0<Z<-1.50)

=0.4901+0.4332=0.9233

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