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Use Tables V, VI, VII, and VIII in Appendix D to find each of the following F-values

  1. \({F_{.05}}\;where\;{v_1} = 9\;and\,{v_2} = 6\)

Short Answer

Expert verified
  1. The F-value is 4.10.

Step by step solution

01

Given Information

Degrees of freedom are

\(\begin{aligned}{v_1} &= {n_1} - 1\\ &= 9\\and\\{v_2} &= {n_2} - 1\\ &= 6\end{aligned}\)

02

Critical value

The probability distribution of a test and its level of significance are used to calculate a critical value. In order to define the confidence interval's boundaries, critical values are used.

03

F-values

\({F_{0.05}}\left( {9,6} \right) = 4.10\)

Therefore, the F-value is 4.10.

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91.28 92.83 89.35 91.90 82.85 94.83 89.83 89.00 84.62

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Standard deviation(n-1)

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