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Patron amenability to supply biomass. Relate to the Biomass and Energy (Vol. 36, 2012) study of the amenability of directors to supply biomass products similar to fat hay, Exercise8.20 (p. 469). Recall that independent samples of Missouri directors and Illinois directors were surveyed. Another aspect of the study concentrated on the service directors who were willing to supply. One essential service involves windrowing (mowing and piling) hay. Of the 558 Missouri directors surveyed, 187 were willing to offer windrowing. Of the 940 Illinois directors surveyed, 380 were willing to offer windrowing services. The experimenters want to know if the proportion of directors willing to offer windrowing services to the biomass request differs for the two areas, Missouri and Illinois.

a. Specify the parameter of interest to the experimenters.

b. Set up the null and indispensable suppositions for testing whether the proportion of directors willing to offer windrowing services differs in Missouri and Illinois.

c. A Minitab analysis of the data is given below. Detect the test statistic on the printout.

d. provide the rejection region for the test using a = .01.

e. Detect the p- the value of the test on the printout.

f. Make the applicable conclusion using both the p-value and rejection region approach. Your conclusions should agree.

Short Answer

Expert verified

A service provides value to consumers by enabling desired results without the ownership of particular potential costs.

Step by step solution

01

Step-by-Step Solution Step 1: Specify the parameter of interest

The parameter of interest is the difference between the proportions of producers who were willing to offer windrowing services to the biomass market area Missouri (p1) and the proportions of producers who were willing to offer windrowing services to the biomass market area Ilinois (p2).

That is, the parameter of interest is P1– P2.

02

Write the null and alternative hypotheses

Null hypothesis:

H0: P₁-P₁=0

There is no difference between the proportions of producers who were willing to offer windrowing services to the biomass market area in Missouri and Illinois.

Alternative hypothesis:

Ha: P₁-P₁≠0

There is a difference between the proportions of producers who were willing to offer windrowing services to the biomass market area in Missouri and Illinois.

03

from the MINITAB, the test statistic

from the MINITAB output, the test statistic (z) value is -2.67.

04

state is a region of rejection

Let the confidence level be 0.99.

1 – α = 0.99

α = 1 – 0.99

= 0.01

a2=0.005

05

From the appendix D table-2

From appendix D- Table2, the value of za/2is given below.

za2= z0.005

= 2.58

So, the value of Za/2 is 2.58 .

Rejection region :

If z > za/2(=2.58), then reject the null hypothesis H0.

If z > za/2(= - 2.58), then reject the null hypothesis H0.

06

Minitab

From the MINITAB output, the p-value is 0.008.

07

conclusion for rejection region approach

The critical value is 2.58, and the value of z is 2.67.

Here, the value is greater than the value of Za/2.

That is, z(= 2.67) > Za/2, (= 2.58).

so,by the rejection rule, reject the null hypothesis (H0).

Thus, it can be concluded that there is evidence to reject the null hypothesis (H0) at α=0.01.

Hence, there is a difference between the proportions of producers willing to supply windrowing services to the biomass market area in Missouri and Illinois.

08

Conclusion for the p-value approach

Use the significance level, α =0.01.

Here p-value is 0.008, which is lesser than the level of significance.

That is, (p-value = 0.008) <(α=0.01).

Therefore, by the condition, If the p-value < α, reject the null hypothesis.

Hence, reject the null hypothesis H0.

Thus, it can be concluded that there is evidence to reject the null hypothesis at a=0.01.

There is a difference between the proportions of producers who were willing to supply windrowing services to the biomass market area in Missouri and Illinois.

Hence, the conclusions obtained from both approaches are the same.

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Most popular questions from this chapter

Assume that σ12222. Calculate the pooled estimator σ2 for each of the following cases:

a.s12=120,s22=100,n1=n2=25

b.s12=12,s22=20,n1=20,n2=10

c.s12=.15,s22=.20,n1=6,n2=10

d.s12=3000,s22=2500,n1=16,n2=17

Note that the pooled estimate is a weighted average of the sample variances. To which of the variances does the pooled estimate fall nearer in each of the above cases?

A paired difference experiment produced the following results:

nd=38,x¯1=92,x¯2=95.5,d¯=-3.5,sd2=21

a. Determine the values zfor which the null hypothesis μ1μ2=0would be rejected in favor of the alternative hypothesis μ1μ2<0 Use .role="math" localid="1652704322912" α=.10

b. Conduct the paired difference test described in part a. Draw the appropriate conclusions.

c. What assumptions are necessary so that the paired difference test will be valid?

d. Find a90% confidence interval for the mean difference μd.

e. Which of the two inferential procedures, the confidence interval of part d or the test of the hypothesis of part b, provides more information about the differences between the population means?

Corporate sustainability of CPA firms. Refer to the Business and Society (March 2011) study on the sustainability behaviors of CPA corporations, Exercise 2.23 (p. 83). Recall that the level of support for corporate sustainability (measured on a quantitative scale ranging from 0 to 160 points) was obtained for each of 992 senior managers at CPA firms. The accompanying Minitab printout gives the mean and standard deviation for the level of support variable. It can be shown that level of support is approximately normally distributed.

a. Find the probability that the level of support for corporate sustainability of a randomly selected senior manager is less than 40 points.

b. Find the probability that the level of support for corporate sustainability of a randomly selected senior manager is between 40 and 120 points.

c. Find the probability that the level of support for corporate sustainability of a randomly selected senior manager is greater than 120 points.

d. One-fourth of the 992 senior managers indicated a level of support for corporate sustainability below what value?

Descriptive Statistics: Support

Variables

N

Mean

StDev

Variance

Minimum

Maximum

Range

Support

992

67.755

26.871

722.036

0.000

155.000

155.000

Question: Independent random samples from approximately normal populations produced the results shown below.

Sample 1

Sample 2

52 33 42 4441 50 44 5145 38 37 4044 50 43

52 43 47 5662 53 61 5056 52 53 6050 48 60 55

a. Do the data provide sufficient evidence to conclude that (μ1-μ2)>10? Test usingα=0.1.

b. Construct a confidence interval for (μ1-μ2). Interpret your result.

Question: A company sent its employees to attend two different English courses. The company is interested in knowing if there is any difference between the two courses attended by its employees. When the employees returned from the courses, the company asked them to take a common test. The summary statistics of the test results of each of the two English courses are recorded in the following table:

a. Identify the parameter(s) that would help the company determine the difference between the two courses.

b. State the appropriate null and alternative hypotheses that the company would like to test.

c. After conducting the hypothesis test at thesignificance level, the company found the p-value. Interpret this result for the company.

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