Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Service without a smile. “Service with a smile” is a slogan that many businesses adhere to. However, some jobs (e.g., judges, law enforcement officers, and pollsters) require neutrality when dealing with the public. An organization will typically provide “display rules” to guide employees on what emotions they should use when interacting with the public. A Journal of Applied Psychology (Vol. 96, 2011) study compared the results of surveys conducted using two different types of display rules: positive (requiring a strong display of positive emotions) and neutral (maintaining neutral emotions at all times). In this designed experiment, 145undergraduate students were randomly assigned to either a positive display rule condition(n1=78)or a neutral display rule condition(n2=67). Each participant was trained to conduct the survey using the display rules. As a manipulation check, the researchers asked each participant to rate, on a scale of 1= “strongly agree” to5= “strongly disagree,” the statement, “This task requires me to be neutral in my expressions.”

a. If the manipulation of the participants was successful, which group should have the larger mean response? Explain.

b. The data for the study (simulated based on information provided in the journal article) are listed in the table above. Access the data and run an analysis to determine if the manipulation was successful. Conduct a test of hypothesis usingα=0.05 .

c. What assumptions, if any, are required for the inference from the test to be valid?

The data is given below

Positive Display Rule:

243333444444444444454444444444444445555555555555555555555555555555555555555555


Neutral Display Rule:

3321211122122232212222212222221222222232122212122322222222222122222


Short Answer

Expert verified

The definition of service is to restore, preserve, and supply something to someone. Clients who are satisfied with the service they get are more inclined to trust and remain committed to the company.

Step by step solution

01

Step-by-Step SolutionStep 1: Calculate the means and standard deviation of both groups

The mean of students displaying Positive Rule =4.4872and the mean of students displaying Neutral Rule = role="math" localid="1652701137112" 1.8955

The standard deviation of students displaying Positive Rule = 0.6595and the standard deviation of students displaying Neutral Rule = 0.4965

02

(a) Find the group having a larger mean response 

The mean response of the positive and neutral groups is4.4872 and1.8955 respectively.

Thus, if the manipulation of the participants is successful, then the positive emotions group has the larger mean response than the neutral emotions group.

Hence, the corresponding members of the groups of positive emotions must disagree with the given statement, which results in a higher response.

03

(b) Conduct z-test

Null Hypothesis: The manipulation was not successful. H0:μ1μ2=0

Alternate Hypothesis: The manipulation was successful Ha:μ1μ2>0

Let the confidence level be 90%.

Level of significance (α)=0.10

So,role="math" localid="1652701587818" α2=0.05and z0.05=1.645

z=x1¯x¯2σ12n1+σ22n2=4.48721.8955(0.6595)278+(0.4965)267=2.59170.0962=26.940

The critical value is1.645

As the value role="math" localid="1652701582886" zis more than the critical value, the null hypothesis should be rejected.

Therefore, the data provide sufficient evidence to indicate thatμ1μ2>0 .

04

(c) State the assumption

The assumption is that independent random samples are selected for each population.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Producer willingness to supply biomass. The conversion of biomass to energy is critical for producing transportation fuels. How willing are producers to supply biomass products such as cereal straw, corn stover, and surplus hay? Economists surveyed producers in both mid-Missouri and southern Illinois (Biomass and Energy, Vol. 36, 2012). Independent samples of 431 Missouri producers and 508 Illinois producers participated in the survey. Each producer was asked to give the maximum proportion of hay produced that they would be willing to sell to the biomass market. Summary statistics for the two groups of producers are listed in the table. Does the mean amount of surplus that hay producers are willing to sell to the biomass market differ for the two areas, Missouri and Illinois? Use a = .05 to make the comparison.

Last name and acquisition timing. Refer to the Journal of Consumer Research (August 2011) study of the last name effect in acquisition timing, Exercise 8.13 (p. 466). Recall that the mean response times (in minutes) to acquire free tickets were compared for two groups of MBA students— those students with last names beginning with one of the first nine letters of the alphabet and those with last names beginning with one of the last nine letters of the alphabet. How many MBA students from each group would need to be selected to estimate the difference in mean times to within 2 minutes of its true value with 95% confidence? (Assume equal sample sizes were selected for each group and that the response time standard deviation for both groups is σ≈ 9 minutes.)

Is honey a cough remedy? Refer to the Archives of Pediatrics and Adolescent Medicine (December 2007) study of honey as a remedy for coughing, Exercise 2.31 (p. 86). Recall that the 105 ill children in the sample were randomly divided into groups. One group received a dosage of an over-the-counter cough medicine (DM); another group received a dosage of honey (H). The coughing improvement scores (as determined by the children’s parents) for the patients in the two groups are reproduced in the accompanying table. The pediatric researchers desire information on the variation in coughing improvement scores for each of the two groups.

a. Find a 90% confidence interval for the standard deviation in improvement scores for the honey dosage group.

b. Repeat part a for the DM dosage group.

c. Based on the results, parts a and b, what conclusions can the pediatric researchers draw about which group has the smaller variation in improvement scores? (We demonstrate a more statistically valid method for comparing variances in Chapter 8.)

Honey Dosage

11 12 15 11 10 13 10 13 10 4 15 16 9 14 10 6 10 11 12 12 8 12 9 11 15 10 15 9 13 8 12 10 9 5 12

DM Dosage

4 6 9 4 7 7 7 9 12 10 11 6 3 4 9 12 7 6 8 12 12 4 12 13 7 10 13 9 4 4 10 15 9

Question: The speed with which consumers decide to purchase a product was investigated in the Journal of Consumer Research (August 2011). The researchers theorized that consumers with last names that begin with letters later in the alphabet will tend to acquire items faster than those whose last names begin with letters earlier in the alphabet—called the last name effect. MBA students were offered free tickets to an event for which there was a limitedsupply of tickets. The first letter of the last name of those who responded to an email offer in time to receive the tickets was noted as well as the response time (measured in minutes). The researchers compared the response times for two groups of MBA students: (1) those with last names beginning with one of the first nine letters of the alphabet and (2) those with last names beginning with one of the last nine letters of the alphabet. Summary statistics for the two groups are provided in the table.

First 9

Letters: A–I

Last 9

Letters: R–Z

Sample size

25

25

Mean response time (minutes)

25.08

19.38

Standard deviation (minutes)

10.41

7.12

Source: Based on K. A. Carlson and J. M. Conrad, “The Last Name Effect: How Last Name Influences Acquisition Timing,” Journal of Consumer Research, Vol. 38, No. 2, August 2011.

a. Construct a 95% confidence interval for the difference between the true mean response times for MBA students in the two groups.

b. Based on the interval, part a, which group has the shorter mean response time? Does this result support the researchers’ last name effect theory? Explain.

4.132 Suppose xis a random variable best described by a uniform

probability distribution with c= 3 and d= 7.

a. Find f(x)

b. Find the mean and standard deviation of x.

c. FindP(μ-σxμ+σ)

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free