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Question: Impact of race on football card values. Refer to the Electronic Journal of Sociology (2007) study of the Impact of race on the value of professional football players’ “rookie” cards, Exercise 12.72 (p. 756). Recall that the sample consisted of 148 rookie cards of NFL players who were inducted into the Football Hall of Fame (HOF). The researchers modelled the natural logarithm of card price (y) as a function of the following independent variables:

Race:x1=1ifblack,0ifwhiteCardavailability:x2=1ifhigh,0iflowCardvintage:x3=yearcardprintedFinalist:x4=naturallogarithmofnumberoftimesplayeronfinalHOFballotPosition-QB::x5=1ifquarterback,0ifnotPosition-RB:x7=1ifrunningback,0ifnotPosition-WR:x8=1ifwidereceiver,0ifnotPosition-TEx9=1iftightend,0ifnotPosition-DL:x10=1ifdefensivelineman,0ifnotPosition-LB:x11=1iflinebacker,0ifnotPosition-DB:x12=1ifdefensiveback,0ifnot

[Note: For position, offensive lineman is the base level.]

  1. The model E(y)=β0+β1x1+β2x2+β3x3+β4x4+β5x5+β6x6+β7x7+β8x8+β9x9+β10x10+β11x11+β12x12 was fit to the data with the following results:R2=0.705,Ra2=0.681,F=26.9.Interpret the results, practically. Make an inference about the overall adequacy of the model.
  2. Refer to part a. Statistics for the race variable were reported as follows:β^1=-0.147,sβ^1=-0.145,t=-1.014,p-value=0.312 .Use this information to make an inference about the impact of race on the value of professional football players’ rookie cards.
  3. Refer to part a. Statistics for the card vintage variable were reported as follows:β^3=-0.074,sβ^3=0.007,t=-10.92,p-value=.000.Use this information to make an inference about the impact of card vintage on the value of professional football players’ rookie cards.
  4. Write a first-order model for E(y) as a function of card vintage x3and position x5-x12that allows for the relationship between price and vintage to vary depending on position.

Short Answer

Expert verified
  1. The value of R2 is 0.705 indicating that nearly 70% of variation in the data is explained by the model. The value of 68.1% for Ra2 indicates that the variables are explaining the model to a higher degree. At 95% significance level, it can be concluded thatthe model is not a good fit for the data.
  2. At95% significance level,β1=0 . Hence it can be concluded with enough evidence that x1 is a significance variable.
  3. At 95% significance level, β3=0. Hence it can be concluded with enough evidence that x2 is a significance variable.
  4. The model is:
  5. Ey=β0+β1x3+β2x5+β3x6+β4x7+β5x8+β6x9+β7x10+β8x11+β9x12+β10x3x5+β11x3x6+β12x3x7+β13x3x8+β14x3x9+β15x3x10+β16x3x11+β17x3x12

.

Step by step solution

01

Given Information

The model is given as-Ey=β0+β1x1+β2x2+β3x3+β4x4+β5x5+β6x6+β7x7+β8x8+β9x9+β10x10+β11x11+β12x12

Where , R2=0.705andRa2=0.681 .

The statistics for the race variable are given asβ^1=-0.147,sβ^1=-0.145,t=-1.014,p-value=0.312 whereas the statistics for the card vintage variable are given as β^3=-0.074,sβ^3=0.007,t=-10.92,p-value=.000 .

02

Interpretation of results

The results got from the model were:R2=0.705,Ra2=0.681,F=26.9. .

Here, the value of R2 is 0.705 indicating that nearly 70% of variation in the data is explained by the model which is very good number. This denotes that the model is a good fit for the data.

Value of ,Ra2=0.681, which adjusts for the added variables and checks if the added variables is explaining the variation in the model or not. The value of 68.1% indicates that the variables are explaining the model to a higher degree.

F-test statistic value is 26.9, to check the overall adequacy of the model, we conduct the f-test.

H0:β1=β2=β3=0

Ha :At least one of the parameters β1,β2,β3 is non zero.

H0:is rejected if F statistic >F0.025,147,147.

For α=0.025,F0.025,147,147=1.311. Since , there is sufficient evidence to reject

Hence the model is not a good fit for the data.

03

 Step 3: Significance of  β1

b.

Here,

H0:β1=0Ha:β10

t-test statistic=β^1sβ^1=-0.1470.145=-1.0137

Value of t0.025,147is 1.98

Ho: is rejected if t statistic>t0.05,24,24 .

For α=0.025, since t<t0.025,147

Not sufficient evidence to reject at 95% confidence interval.

Therefore, β1=0. Hence it can be concluded with enough evidence that x1 is a significant variable.

04

Significance of  β2 

c.

H0:β3=0Ha:β30

Here,

t-teststatistic=β^3sβ^3=-0.0740.007=-10.57

Value of t0.025,147 is 1.98

H0 is rejected if t statistic >t0.05,24,24. For α=0.025, since t<t0.025,147

Not sufficient evidence to reject H0 at 95% confidence interval.

Therefore,β3=0. Hence it can be concluded with enough evidence that x3 is a significant variable.

05

Model equation

d.

To write a first-order model for E(y) as a function of card vintage x3 and position x5-x12 that allows the relationship between price and vintage to vary depending on the position can be expressed by an interaction model.

The equation can be written as:

.Ey=β0+β1x3+β2x5+β3x6+β4x7+β5x8+β6x9+β7x10+β8x11+β9x12+β10x3x5+β11x3x6+β12x3x7+β13x3x8+β14x3x9+β15x3x10+β16x3x11+β17x3x12

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