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Bankruptcy effect on U.S. airfares. Both Delta Airlines and USAir filed for bankruptcy. A study of the impact of bankruptcy on the fares charged by U.S. airlines was published in Research in Applied Economics (Vol. 2, 2010). The researchers collected data on Orlando-bound airfares for three airlines—Southwest (a stable airline), Delta (just entering bankruptcy at the time), and USAir (emerging from bankruptcy). A large sample of nonrefundable ticket prices was obtained for each airline following USAir’s emergence from bankruptcy, and then a 95% confidence interval for the true mean airfare was obtained for each. The results for 7-day advance bookings are shown in the accompanying table.

a. What confidence coefficient was used to generate the confidence intervals?

b. Give a practical interpretation of each of the 95% confidence intervals. Use the phrase “95% confident” in your answer.

c. When you say you are “95% confident,” what do you mean?

d. If you want to reduce the width of each confidence interval, should you use a smaller or larger confidence coefficient?

Short Answer

Expert verified

a. The confidence coefficient that was used to generate the confidence intervals is 0.95.

b. There is 95% confidence that the true mean airfare for the airline “Southwest” lies between $412 and $495.There is 95% confidence that the true mean airfare for the airline “Delta” lies between $468 and $500.There is 95% confidence that the true mean airfare for the airline “USAir” lies between $247 and $372.

c. The 95% of all similarly generated confidence intervals will contain the true value of the population meanin repeated sampling.

d. The smaller confidence coefficient should be used to reduce the width of the confidence interval because the smaller confidence coefficient leads to the smaller width of the confidence interval.

Step by step solution

01

Given information

A large sample of nonrefundable ticket prices was obtained for each airline following USAir’s emergence from bankruptcy, and then a 95% confidence interval for the true mean airfare was obtained for each. The results for 7-day advance bookings are shown in the accompanying table.

02

(a) Interpretation for confidence intervals

The confidence coefficient that was used to generate the confidence intervals is 0.95.

03

(b)Interpretation

Interpretation for the airline “Southwest”:There is 95% confidence that the true mean airfare for the airline “Southwest” lies between $412 and $495.

Interpretation for the airline “Delta”:There is 95% confidence that the true mean airfare for the airline “Delta” lies between $468 and $500.

Interpretation for the airline “USAir”:There is 95% confidence that the true mean airfare for the airline “USAir” lies between $247 and $372.

Step 3: (c) Interpretation for confidence intervals

The 95% of all similarly generated confidence intervals will contain the true value of the population meanμ in repeated sampling.

04

(d) Interpretation of confidence coefficient

The smaller confidence coefficient should be used to reduce the width of the confidence interval because the smaller confidence coefficient leads to the smaller width of the confidence interval.

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Most popular questions from this chapter

Question: Consumers’ attitudes toward advertising. The two most common marketing tools used for product advertising are ads on television and ads in a print magazine. Consumers’ attitudes toward television and magazine advertising were investigated in the Journal of Advertising (Vol. 42, 2013). In one experiment, each in a sample of 159 college students were asked to rate both the television and the magazine marketing tool on a scale of 1 to 7 points according to whether the tool was a good example of advertising, a typical form of advertising, and a representative form of advertising. Summary statistics for these “typicality” scores are provided in the following table. One objective is to compare the mean ratings of TV and magazine advertisements.

a. The researchers analysed the data using a paired samples t-test. Explain why this is the most valid method of analysis. Give the null and alternative hypotheses for the test.

b. The researchers reported a paired t-value of 6.96 with an associated p-value of .001 and stated that the “mean difference between television and magazine advertising was statistically significant.” Explain what this means in the context of the hypothesis test.

c. To assess whether the result is “practically significant,” we require a confidence interval for the mean difference. Although this interval was not reported in the article, you can compute it using the information provided in the table. Find a 95% confidence interval for the mean difference and interpret the result. What is your opinion regarding whether the two means are “practically significant.”

Source: H. S. Jin and R. J. Lutz, “The Typicality and Accessibility of Consumer Attitudes Toward Television Advertising: Implications for the Measurement of Attitudes Toward Advertising in General,” Journal of Advertising, Vol. 42, No. 4, 2013 (from Table 1)

Question: The speed with which consumers decide to purchase a product was investigated in the Journal of Consumer Research (August 2011). The researchers theorized that consumers with last names that begin with letters later in the alphabet will tend to acquire items faster than those whose last names begin with letters earlier in the alphabet—called the last name effect. MBA students were offered free tickets to an event for which there was a limitedsupply of tickets. The first letter of the last name of those who responded to an email offer in time to receive the tickets was noted as well as the response time (measured in minutes). The researchers compared the response times for two groups of MBA students: (1) those with last names beginning with one of the first nine letters of the alphabet and (2) those with last names beginning with one of the last nine letters of the alphabet. Summary statistics for the two groups are provided in the table.

First 9

Letters: A–I

Last 9

Letters: R–Z

Sample size

25

25

Mean response time (minutes)

25.08

19.38

Standard deviation (minutes)

10.41

7.12

Source: Based on K. A. Carlson and J. M. Conrad, “The Last Name Effect: How Last Name Influences Acquisition Timing,” Journal of Consumer Research, Vol. 38, No. 2, August 2011.

a. Construct a 95% confidence interval for the difference between the true mean response times for MBA students in the two groups.

b. Based on the interval, part a, which group has the shorter mean response time? Does this result support the researchers’ last name effect theory? Explain.

Find the following probabilities for the standard normal random variable z:

a.P(0<z<2.25)b.P(-2.25<z<0)b.P(-2.25<z<1.25)d.P(-2.50<z<1.50)e.P(z<-2.33orz>2.33)

4.134 Refer to Exercise 4.133. Find the following probabilities:

a.P(20x30)b.P(20<x30)c.P(x30)d.P(x45)e.(x40)f.(x<40)g.P(15x35)h.P(21.5x31.5)

Given that x is a random variable for which a Poisson probability distribution provides a good approximation, use statistical software to find the following:

a.P(x2) when λ=1

b.P(x2) when λ=2

c.P(x2) when λ=3

d. What happens to the probability of the event {x2} as λ it increases from 1 to 3? Is this intuitively reasonable?

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