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Entrepreneurial careers of MBA alumni. Are African American MBA scholars more likely to begin their careers as entrepreneurs than white MBA scholars? This was a question of interest to the Graduate Management Admission Council (GMAC). GMAC Research Reports (Oct. 3, 2005) published the results of a check of MBA alumni. Of the African Americans who responded to the check, 209 reported their employment status after scaling as tone-employed or a small business proprietor. Of the whites who responded to the check, 356 reported their employment status after scaling as tone-employed or a small business proprietor. Use this information to answer the exploration question.

Short Answer

Expert verified

We have enough evidence to conclude that African American MBA students are more likely to begin their careers as an entrepreneur than White MBA students.

Step by step solution

01

Sample the proportion of the two groups

in a survey of 1304 African American MBA alumnus, 209 reported their employment status as self-employed or a small business owner. Of 7,120 whites, 356 reported their employment status as self-employed or a small business owner.

Therefore, we have the sample proportion of the two groups as follows:

P1 =

= 0.1603

PTwo=

=0.05

02

Set the null and alternative hypotheses

Here we have to test whether there is enough evidence to claim that African American MBA students are more likely to begin their careers as entrepreneurs than White MBA students.

As a result, we establish the null as well as alternative hypotheses as shown in:

H0: (P1 –P2) = 0

Versus

Ha:(P₁-P₂)>0

This is a right-tailed test.

Also, we set a = 0.05 level of significance.

03

Sample distribution of (P1-P2)

As per the requirement, we find the following value.

n1p1= x1

= 209(>15)

n2q2= n1 – x1

= 1304 - 209

= 1095(>15)

n2q2= x2

= 356(>15)

n2q2= n2– x2

= 7120 – 356

=6764(>15)

Thus, the given samples are large. Therefore, the sampling distribution of (P1-P2) will be approximately normal.

04

Test statistics

The statistical tests for the null hypothesis are as follows:

z=

where = =

Using MINITAB, we conduct the above test in the following steps.

Step 1: Select 2 Proportions... from the Basic Statistics of Stat ribbon.

Step 2: Enter the Events and Trails as 209 and 1304 for the First sample and 356 and 7120 for the second sample in the Summarized data.

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Consider the discrete probability distribution shown here.

x

10

12

18

20

p

.2

.3

.1

.4

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b. What isP(x<15) ?

c. Calculate μ±2σ .

d. What is the probability that xis in the interval μ±2σ ?

To use the t-statistic to test for a difference between the means of two populations, what assumptions must be made about the two populations? About the two samples?

Question: Two independent random samples have been selected—100 observations from population 1 and 100 from population 2. Sample means x¯1=26.6,x¯2= 15.5 were obtained. From previous experience with these populations, it is known that the variances areσ12=9andσ22=16 .

a. Find σ(x¯1-x¯2).

b. Sketch the approximate sampling distribution for (x¯1-x¯2), assuming (μ1-μ2)=10.

c. Locate the observed value of (x¯1-x¯2)the graph you drew in part

b. Does it appear that this value contradicts the null hypothesis H0:(μ1-μ2)=10?

d. Use the z-table to determine the rejection region for the test againstH0:(μ1-μ2)10. Useα=0.5.

e. Conduct the hypothesis test of part d and interpret your result.

f. Construct a confidence interval for μ1-μ2. Interpret the interval.

g. Which inference provides more information about the value of μ1-μ2— the test of hypothesis in part e or the confidence interval in part f?

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