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Fish contaminated by a plant’s discharge. Refer (Example 1.5, p. 38) to the U.S. Army Corps of Engineers data on a sample of 144 contaminated fish collected from the river adjacent to a chemical plant. Estimate the proportion of contaminated fish that are of the channel catfish species. Use a 90% confidence interval and interpret the result.

Short Answer

Expert verified

It is 90% confident that, the true proportion of contaminated fish that are of the channel catfish species is between 0.603 and 0.731.

Step by step solution

01

Given information

The U.S army Corps of Engineers data on a sample of 144 contaminated fish collected from the river adjacent to a chemical plant. That is, the sample size is n=144.Let X be the number of catfish species, that is x=96.

02

Calculating the population proportion and its confidence interval

Let,

Proportion of contaminated fish that are of the chemical catfish species is

p^=xn=96144=0.667

To ensure that sample size is sufficiently large that the normal distribution provides a reasonable approximation for the sampling distribution of, it require both np^ and nq^to be at least 15. That is, np^15and nq^15.

Here np^and nq^are the number of successes and number of failures, respectively, in the sample.

Now,

np^=144×0.667=96.048

nq^=144×1-0.667=47.952

np^and nq^values are at least 15, it may assume that the normal approximation is reasonable and can conclude that the sample size is sufficiently large.

The 90% confidence intervals for true proportion is,

p^±1.645p^q^n=0.667±1.6450.6671-0.667144=0.667±0.064=0.603,0.731

Hence, it is 90% confident that, the true proportion of contaminated fish that are of the channel catfish species is between 0.603 and 0.731.

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