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Question: The hot tamale caper. “Hot tamales” are chewy, cinnamonflavored candies. A bulk vending machine is known to dispense, on average, 15 hot tamales per bag with a standard deviation of 3 per bag. Chance (Fall 2000) published an article on a classroom project in which students were required to purchase bags of hot tamales from the machine and count the number of candies per bag. One student group claimed they purchased five bags that had the following candy counts: 25, 23, 21, 21, and 20. These data are saved in the file. There was some question as to whether the students had fabricated the data. Use a hypothesis test to gain insight into whether or not the data collected by the students were fabricated. Use a level of significance that gives the benefit of the doubt to the students

Short Answer

Expert verified

It is concluded that the data collected by the students were not fabricated.

Step by step solution

01

Given information

The mean number of hot tamales per bag is 15 with standard deviation 3 per kg.

It is given that the total bags are 5 with following candy counts: 25, 23, 21, 21 and 20

02

Concept of t test statistic

If the sample size is less than 30 then the hypotheses are tested using t test statistic.

The t test statistic is calculated using the following formula

03

Calculating the mean and the standard deviation

Since, the mean is calculated using the following formula,

Therefore,

Also, the variance is calculated using the following formula,

Therefore,

04

Testing the hypotheses

Consider the null and the alternative hypothesis as follows,

H0 : µ = 15

That is, the data collected by the students were fabricated.

H0 : µ ≠ 15

That is, the data collected by the students were not fabricated.

Test statistic to test the above hypotheses is given as,

Therefore,

Now,

Level of significance, α = 0.5

Degrees of freedom, n - 1 = 4

Also, this is two tailed test.

So, from the t distribution table, the tabulated values are -2.7764 and 2.7764.

Here, t < -2.7764 and t > 2.7764.

Since, the test statistic lies in the Rejection Region, therefore the null hypothesis is rejected.So, it may conclude that the data collected by the students were not fabricated.

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Most popular questions from this chapter

Question:Accounting and Machiavellianism. Refer to the Behavioral Research in Accounting (January 2008) study of Machiavellian traits in accountants, Exercise 6.19 (p. 341). A Mach rating score was determined for each in a random sample of 122 purchasing managers, with the following results: = 99.6 s = 12.6. Recall that a director of purchasing at a major firm claims that the true mean Mach rating score of all purchasing managers is 85.

a. Suppose you want to test the director’s claim. Specify the null and alternative hypotheses for the test.

b. Give the rejection region for the test using α = 0.10.

c. Find the value of the test statistic.

d. Use the result, part c, to make the appropriate conclusion.

Salaries of postgraduates. The Economics of Education Review (Vol. 21, 2002) published a paper on the relationship between education level and earnings. The data for the research was obtained from the National Adult Literacy Survey of more than 25,000 respondents. The survey revealed that males with a postgraduate degree have a mean salary of \(61,340 (with standard error \(Sx\) = \)2,185), while females with a postgraduate degree have a mean of \(32,227 (with standard error \(Sx\) = \)932).

  1. The article reports that a 95% confidence interval for \[{\bf{\mu }}M\] , the population mean salary of all males with post-graduate degrees, is (\(57,050, \)65,631). Based on this interval, is there evidence to say that \[{\bf{\mu }}M\] differs from \(60,000? Explain.
  2. Use the summary information to test the hypothesis that the true mean salary of males with postgraduate degrees differs from \)60,000. Use \(\alpha \) =.05.
  3. Explain why the inferences in parts a and b agree.
  4. The article reports that a 95% confidence interval for \(\mu F\) , the population mean salary of all females with post-graduate degrees, is (\(30,396, \)34,058). Based on this interval, is there evidence to say that \(\mu F\)differs from \(33,000? Explain.
  5. Use the summary information to test the hypothesis that the true mean salary of females with postgraduate degrees differs from \)33,000. Use \(\alpha \) =.05.
  6. Explain why the inferences in parts d and e agree.

A sample of five measurements, randomly selected from a normally distributed population, resulted in the following summary statistics: \(\bar x = 4.8\), \(s = 1.3\) \(\) .

a. Test the null hypothesis that the mean of the population is 6 against the alternative hypothesis, µ<6. Use\(\alpha = .05.\)

b. Test the null hypothesis that the mean of the population is 6 against the alternative hypothesis, µ\( \ne 6\). Use\(\alpha = .05.\)

c. Find the observed significance level for each test.

Refer to Exercise 7.99.

a. Find b for each of the following values of the population mean: 74, 72, 70, 68, and 66.

b. Plot each value of b you obtained in part a against its associated population mean. Show b on the vertical axis and m on the horizontal axis. Draw a curve through the five points on your graph.

c. Use your graph of part b to find the approximate probability that the hypothesis test will lead to a Type II error when m = 73.

d. Convert each of the b values you calculated in part a to the power of the test at the specified value of m. Plot the power on the vertical axis against m on the horizontal axis. Compare the graph of part b with the power curve of this part.

e. Examine the graphs of parts b and d. Explain what they reveal about the relationships among the distance between the true mean m and the null hypothesized mean m0, the value of b, and the power.

For each of the following situations, determine the p-value and make the appropriate conclusion.

a.\({H_0}:\mu \le 25\),\({H_a}:\mu > 25\),\(\alpha = 0.01\),\(z = 2.02\)

b.\({H_0}:\mu \ge 6\),\({H_a}:\mu < 6\),\(\alpha = 0.05\),\(z = - 1.78\)

c.\({H_0}:\mu = 110\),\({H_a}:\mu \ne 110\),\(\alpha = 0.1\),\(z = - 1.93\)

d. \({H_0}:\mu = 10\), \({H_a}:\mu \ne 10\), \(\alpha = 0.05\), \(z = 1.96\)

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