Chapter 6: Problem 10
Show that strict stationarity of a time series \(\left\\{Y_{j}\right\\}\) means that for any \(r\) we have $$ \operatorname{cum}\left(Y_{j_{1}}, \ldots, Y_{j_{r}}\right)=\operatorname{cum}\left(Y_{0}, \ldots, Y_{j_{r}-j_{1}}\right)=\kappa^{j_{2}-j_{1}, \ldots, j_{r}-j_{1}} $$ say. Suppose that \(\left\\{Y_{j}\right\\}\) is stationary with mean zero and that for each \(r\) it is true that \(\sum_{u}\left|\kappa^{u_{1}, \ldots, u_{r-1}}\right|=c_{r}<\infty\) The \(r\) th cumulant of \(T=n^{-1 / 2}\left(Y_{1}+\cdots+Y_{n}\right)\) is $$ \begin{aligned} \operatorname{cum}\left\\{n^{-1 / 2}\left(Y_{1}+\cdots+Y_{n}\right)\right\\} &=n^{-r / 2} \sum_{j_{1}, \ldots, j_{r}} \operatorname{cum}\left(Y_{j_{1}}, \ldots, Y_{j_{r}}\right) \\ &=n^{-r / 2} \sum_{j_{1}=1}^{n} \sum_{j_{2}, \ldots, j_{r}} \kappa^{j_{2}-j_{1}, \ldots, j_{r}-j_{1}} \\ &=n \times n^{-r / 2} \sum_{j_{2}, \ldots, j_{r}} \kappa^{j_{2}-j_{1}, \ldots, j_{r}-j_{1}} \\ & \leq n^{1-r / 2} \sum_{j_{2}, \ldots, j_{r}}\left|\kappa^{j_{2}-j_{1}, \ldots, j_{r}-j_{1}}\right| \leq n^{1-r / 2} c_{r} \end{aligned} $$ Justify this reasoning, and explain why it suggests that \(T\) has a limiting normal distribution as \(n \rightarrow \infty\), despite the dependence among the \(Y_{j}\). Obtain the cumulants of \(T\) for the MA(1) model, and convince yourself that your argument extends to the \(\mathrm{MA}(q)\) model. Can you extend the argument to arbitrary linear combinations of the \(Y_{j} ?\)
Short Answer
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Key Concepts
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