Chapter 12: Problem 7
Let \(X\) and \(Y\) be independent exponential variables with means \(\gamma^{-1}\) and \((\gamma \psi)^{-1}\). Show that the parameter \(\lambda(\gamma, \psi)\) orthogonal to \(\psi\) is the solution to the equation \(\partial \gamma / \partial \psi=-\gamma /(2 \psi)\), and verify that taking \(\lambda=\gamma / \psi^{-1 / 2}\) yields an orthogonal parametrization. Investigate how this solution changes when \(X\) and \(Y\) are subject to Type I censoring at \(c\).
Short Answer
Step by step solution
Express Exponential Variables in Terms of Rates
Define the Desired Orthogonality Condition
Setup the Orthogonality Equation
Calculate Partial Derivative of Proposed \(\lambda\)
Verifying Orthogonality Condition
Evaluate Changes Under Type I Censoring
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Orthogonal Parameters
To determine whether a set of parameters is orthogonal, consider the partial derivative condition. For a parameter \(\lambda(\gamma, \psi)\) to be orthogonal to \(\psi\), the partial derivative of \(\lambda\) with respect to \(\psi\) must equal zero: \(\frac{\partial \lambda}{\partial \psi} = 0\).
In the exercise, we demonstrate that by defining \(\lambda = \gamma / \psi^{-1/2}\), the orthogonality condition is satisfied because the partial derivative \(\frac{\partial \lambda}{\partial \psi}\) correctly simplifies to correspond with the equation condition given. This fulfillment ensures that our parameters are indeed orthogonal.
Understanding orthogonal parameters is crucial because they simplify the estimation process by reducing the correlation between estimates, leading to more efficient statistical analyses.
Exponential Distribution
An exponential random variable \(X\) with rate parameter \(\gamma\) has a probability density function given by \(f_X(x; \gamma) = \gamma e^{-\gamma x}\). Similarly, when we include another parameter \(\psi\), the rate of \(Y\) becomes \(\gamma \psi\) and its density function is \(f_Y(y; \gamma, \psi) = \gamma \psi e^{-(\gamma \psi) y}\).
The mean of an exponential distribution with rate \(\rho\) is given by \(1/\rho\), which is why our exercise involves independent exponential variables with means \(\gamma^{-1}\) and \((\gamma \psi)^{-1}\), indicating their rates.
The appeal of the exponential distribution lies in its simplicity and applicability to numerous real-world processes where the time until an event follows an exponential pattern.
Type I Censoring
In our setup, considering Type I censoring at time \(c\), any data past this time point is not observed. The probability densities for our exponential variables, when subject to this type of censoring, are adjusted to reflect this limitation. The censored densities are expressed as \(f_X^*(x; \gamma) = \gamma e^{-\gamma x} / P(X \leq c)\) and \(f_Y^*(y; \gamma, \psi) = \gamma \psi e^{-(\gamma \psi) y} / P(Y \leq c)\).
This modification incorporates the probability of observing a time \(X \leq c\) or \(Y \leq c\), acknowledging the censored nature of the data and ensuring accurate statistical inference.
Partial Derivative in Statistics
When finding the partial derivative of \(\lambda = \gamma / \psi^{-1/2}\), we apply the chain rule. The derivative is calculated as \(\frac{\partial \lambda}{\partial \psi} = \gamma \times \frac{1}{2} \psi^{-1/2} = \frac{\gamma}{2 \psi^{-1/2}}\). This partial derivative is compared against our orthogonality condition, ensuring that setting \(\lambda = \gamma / \psi^{-1/2}\) appropriately meets the criteria needed for orthogonal parameters.
In essence, understanding the role of partial derivatives is fundamental in parameter estimation, helping to convey how each variable contributes to the structure and dependencies within statistical models.