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Suppose that \(n\) independent Poisson processes of rates \(\lambda_{j}(y)\) are observed simultaneously, and that the \(m\) events occur at \(0c_{j}\). If \(\mathcal{R}_{i}\) is the set \(\left\\{j: V_{j}\left(y_{i}\right)=1\right\\}\), show that the second term in (10.67) equals $$ \prod_{i=1}^{m} \frac{\xi\left\\{\beta ; x_{j_{i}}\left(y_{i}\right)\right\\}}{\sum_{j \in \mathcal{R}_{i}} \xi\left\\{\beta ; x_{j}\left(y_{i}\right)\right\\}} $$ How does this specialize for time-varying explanatory variables in the proportional hazards model?

Short Answer

Expert verified
Calculate the probability of events occurring and interpret them for varying rates and conditions in Poisson processes.

Step by step solution

01

Understand Poisson Process

A Poisson process describes a series of events happening with a certain rate, which is defined by the function \(\lambda_j(y)\). In this exercise, we work with several such processes occurring simultaneously, each one associated with a rate function.
02

Calculate Probability of First Event Occurrence

The probability that the first event occurs at \(y_1\) is the sum of the rates of all processes at that point multiplied by an exponential factor which accounts for no events happening before \(y_1\). Specifically: \[p(y_1) = \left\{\sum_{j=1}^{n} \lambda_{j}(y_{1})\right\} \exp\left\{-\sum_{j=1}^{n} \int_{0}^{y_{1}} \lambda_{j}(u) du\right\}.\]
03

Find Probability of Event Type

Given that an event happens at \(y_1\), its probability being of type \(j_1\) is the rate of the particular process divided by the sum of the rates at that time:\[p(j_1 | y_1) = \frac{\lambda_{j_{1}}(y_{1})}{\sum_{j=1}^{n} \lambda_{j}(y_{1})}.\]
04

Interpret Combined Probability Expressions

The expression \[\exp\left\{-\sum_{j=1}^{n} \int_{0}^{y_{0}} \lambda_{j}(u) du\right\} \prod_{i=1}^{m}\left\{\sum_{j=1}^{n} \lambda_{j}(y_{i})\right\}\] calculates the joint density for multiple events, considering occurrences across different times and all processes. The term \[\prod_{i=1}^{m} \frac{\lambda_{j_{i}}(y_{i})}{\sum_{j=1}^{n} \lambda_{j}(y_{i})}\] represents the product of probabilities for each event type at their respective times.
05

Apply for Time-Varying Explanatory Variables

For each process, \(\lambda_{j}(y) = h_{0}(y) \xi\{\beta ; x_{j}(y)\} V_{j}(y)\), where the process depends on a rate influenced by external features (covariates). The probability for event-type distribution simplifies to:\[\prod_{i=1}^{m} \frac{\xi\{\beta ; x_{j_{i}}(y_{i})\}}{\sum_{j \in \mathcal{R}_{i}} \xi\{\beta ; x_{j}(y_{i})\}}.\]This mirrors how explanatory variables affect the likelihood of events in proportional hazard models.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability of First Event
When dealing with multiple processes such as in the given scenario, the question arises: "What is the probability that the very first event happens at a specific time, say \( y_1 \)?" To unpack this, imagine you are watching several independent Poisson processes, each ticking away with their rate function \( \lambda_j(y) \).
You'll want to know when one of these tickings results in an event occurring. The formula to calculate this is:
  • First, sum up the rates of all \( n \) processes at time \( y_1 \). This gives the collective potential for an event to happen at that instant.
  • Then, multiply this by the exponential function that represents the lack of events before time \( y_1 \). Essentially, it's expressed as \( \exp \left\{ -\sum_{j=1}^{n} \int_{0}^{y_{1}} \lambda_{j}(u) \mathrm{d}u \right\} \).
The larger this exponential term is, the smaller the probability of an event before \( y_1 \), thus the greater the importance of events happening precisely at \( y_1 \). Understanding this helps appreciate how events can sporadically occur across different processes and times.
Time-Varying Covariates
In advanced statistical models like these, time-varying covariates play an exceptional role. They are variables that change over time, influencing the rate at which events occur in each process. In the given problem, each process has a rate \( \lambda_j(y) = h_0(y) \xi\{\beta; x_j(y)\} V_j(y) \), which is shaped by:
  • A baseline hazard function \( h_0(y) \) that sets the basic rhythm of occurrences without any external influence.
  • The function \( \xi\{\beta; x_j(y)\} \), which is a modifier depending on parameters \( \beta \) and covariates \( x_j(y) \) – reflecting the impact of varying conditions on the event likelihood.
  • A switch \( V_j(y) \) indicating whether a process is observable or censored at any given moment.
Through these covariates, models can dynamically adjust their expectations about process rates based on external criteria, offering a more realistic depiction of event probabilities in practice. This dynamic adjustment becomes particularly critical when processes are investigated over varying periods.
Proportional Hazards Model
The proportional hazards model is a cornerstone of survival analysis, often used to examine the time to an event, such as failure or death. It builds a picture of how different factors affect the timing of an event. Essential to this model is the integration of time-varying covariates, especially as they impact the rate function already discussed.
Here's how it applies in this context:
  • The model assumes that the effects of covariates are proportional over time – meaning that while the baseline hazard \( h_0(y) \) continues, the effect of covariates is multiplicative, without changing the baseline shape.
  • When events happen, the probability of each process type is calculated using \( \xi\{\beta; x_{j_{i}}(y_{i})\} \) for the observed values and dividing by the sum for all observed processes \( \sum_{j \in \mathcal{R}_{i}} \xi\{\beta; x_j(y_i)\} \).
This approach allows the researcher to pinpoint and measure how specific factors alter the hazard or risk of the event happening at any given moment. It advances insights into not just the timing but the driving forces behind occurrences by linking them with observable variables.

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Most popular questions from this chapter

Suppose that \(Y\) has a density with generalized linear model form $$ f(y ; \theta, \phi)=\exp \left\\{\frac{y \theta-b(\theta)}{a(\phi)}+c(y ; \phi)\right\\} $$ where \(\theta=\theta(\eta)\) and \(\eta=\beta^{\mathrm{T}} x\). (a) Show that the weight for iterative weighted least squares based on expected information is $$ w=b^{\prime \prime}(\theta)(d \theta / d \eta)^{2} / a(\phi) $$ and deduce that \(w^{-1}=V(\mu) a(\phi)\\{d g(\mu) / d \mu\\}^{2}\), where \(V(\mu)\) is the variance function, and that the adjusted dependent variable is \(\eta+(y-\mu) d g(\mu) / d \mu\). Note that initial values are not required for \(\beta\), since \(w\) and \(z\) can be determined in terms of \(\eta\) and \(\mu\); initial values can be found from \(y\) as \(\mu^{1}=y\) and \(\eta^{1}=g(y)\). (b) Give explicit formulae for the weight and adjusted dependent variable when \(R=m Y\) is binomial with denominator \(m\) and probability \(\pi=e^{\eta} /\left(1+e^{\eta}\right)\).

In \((10.17)\), suppose that \(\phi_{j}=\phi a_{j}\), where the \(a_{j}\) are known constants, and that \(\phi\) is functionally independent of \(\beta .\) Show that the likelihood equations for \(\beta\) are independent of \(\phi\), and deduce that the profile log likelihood for \(\phi\) is $$ \ell_{\mathrm{p}}(\phi)=\phi^{-1} \sum_{j=1}^{n}\left\\{\frac{y_{j} \widehat{\theta}_{j}-b\left(\widehat{\theta}_{j}\right)}{a_{j}}+c\left(y_{j} ; \phi a_{j}\right)\right\\} $$ Hence show that for gamma data the maximum likelihood estimate of \(v\) solves the equation \(\left.\log \nu-\psi(v)=n^{-1} \sum_{(} z_{j}-\log z_{j}-1\right)\), where \(z_{j}=y_{j} / \widehat{\mu}_{j}\) and \(\psi(v)\) is the digamma function \(d \log \Gamma(v) / d \nu\)

A positive stable random variable \(U\) has \(\mathrm{E}\left(e^{-s U}\right)=\exp \left(-\delta s^{\alpha} / \alpha\right), 0<\alpha \leq 1\) (a) Show that if \(Y\) follows a proportional hazards model with cumulative hazard function \(u \exp \left(x^{\mathrm{T}} \beta\right) H_{0}(y)\), conditional on \(U=u\), then \(Y\) also follows a proportional hazards model unconditionally. Are \(\beta, \alpha\), and \(\delta\) estimable from data with single individuals only? (b) Consider a shared frailty model, as in the previous question, with positive stable \(U\). Show that the joint survivor function may be written as $$ \mathcal{F}\left(y_{1}, y_{2}\right)=\exp \left(-\left[\left\\{-\log \mathcal{F}_{1}\left(y_{1}\right)\right\\}^{1 / \alpha}+\left\\{-\log \mathcal{F}_{2}\left(y_{2}\right)\right\\}^{1 / \alpha}\right]^{\alpha}\right), \quad y_{1}, y_{2}>0 $$ in terms of the marginal survivor functions \(\mathcal{F}_{1}\) and \(\mathcal{F}_{2}\). Show that if the conditional cumulative hazard functions are Weibull, \(u H_{r}(y)=u \xi_{r} y^{\gamma}, \gamma>0, r=1,2\), then the marginal survivor functions are also Weibull. Show also that the time to the first event has a Weibull distribution.

Consider independent exponential variables \(Y_{j}\) with densities \(\lambda_{j} \exp \left(-\lambda_{j} y_{j}\right)\), where \(\lambda_{j}=\) \(\exp \left(\beta_{0}+\beta_{1} x_{j}\right), j=1, \ldots, n\), where \(x_{j}\) is scalar and \(\sum x_{j}=0\) without loss of generality. (a) Find the expected information for \(\beta_{0}, \beta_{1}\) and show that the maximum likelihood estimator \(\widehat{\beta}_{1}\) has asymptotic variance \(\left(n m_{2}\right)^{-1}\), where \(m_{2}=n^{-1} \sum x_{j}^{2}\) (b) Under no censoring, show that the partial log likelihood for \(\beta_{1}\) equals $$ -\sum_{j=1}^{n} \log \left\\{\sum_{i=j}^{n} \exp \left(\beta_{1} x_{(i)}\right)\right\\} $$ where the elements of the rank statistic \(R=\\{(1), \ldots,(n)\\}\) are determined by the ordering on the failure times, \(y_{(1)}<\cdots

At each of the doses \(x_{1}0\) is used, show that $$ \widehat{\beta}=\frac{1}{x_{0}} \Phi^{-1}(r / m), \quad \operatorname{var}(\widehat{\beta}) \doteq \frac{\Phi\left(\beta x_{0}\right)\left\\{1-\Phi\left(\beta x_{0}\right)\right\\}}{m x_{0}^{2}\left\\{\phi\left(\beta x_{0}\right)\right\\}^{2}} $$ where \(\phi\) and \(\Phi\) are the standard normal density and distribution functions. Plot the function \(\Phi(\eta)\\{1-\Phi(\eta)\\} / \phi(\eta)^{2}\) for \(\eta\) in the range \(-3 \leq \eta \leq 3\), and comment on the implications for the choice of \(x_{0}\) if there is some prior knowledge of the likely value of \(\beta\).

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