Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Suppose that \(Y\) has a density with generalized linear model form $$ f(y ; \theta, \phi)=\exp \left\\{\frac{y \theta-b(\theta)}{a(\phi)}+c(y ; \phi)\right\\} $$ where \(\theta=\theta(\eta)\) and \(\eta=\beta^{\mathrm{T}} x\). (a) Show that the weight for iterative weighted least squares based on expected information is $$ w=b^{\prime \prime}(\theta)(d \theta / d \eta)^{2} / a(\phi) $$ and deduce that \(w^{-1}=V(\mu) a(\phi)\\{d g(\mu) / d \mu\\}^{2}\), where \(V(\mu)\) is the variance function, and that the adjusted dependent variable is \(\eta+(y-\mu) d g(\mu) / d \mu\). Note that initial values are not required for \(\beta\), since \(w\) and \(z\) can be determined in terms of \(\eta\) and \(\mu\); initial values can be found from \(y\) as \(\mu^{1}=y\) and \(\eta^{1}=g(y)\). (b) Give explicit formulae for the weight and adjusted dependent variable when \(R=m Y\) is binomial with denominator \(m\) and probability \(\pi=e^{\eta} /\left(1+e^{\eta}\right)\).

Short Answer

Expert verified
The weight \(w\) for IWLS is derived from the variance function and transformations between \(\theta\) and \(\eta\). For a binomial case, \(w = \pi (1 - \pi) m\) and the adjusted variable \(z = \eta + (y - \mu) \frac{1}{\mu(1 - \mu)}\).

Step by step solution

01

Understanding the given density function

The given density function is expressed in a generalized linear model form: \[f(y ; \theta, \phi) = \exp \left\{\frac{y \theta - b(\theta)}{a(\phi)} + c(y; \phi)\right\}\]This form highlights the roles of \(\theta\) and \(\phi\), where \(\theta\) is linked to the linear predictor \(\eta\) through \(\theta = \theta(\eta)\) and \(\eta = \beta^{\mathrm{T}} x\).
02

Calculating the weight for IWLS

The weight \(w\) in iterative weighted least squares (IWLS) is based on expected information and is derived from the second derivative of the log-likelihood with respect to \(\theta\). The formula is:\[w = b''(\theta)\left(\frac{d\theta}{d\eta}\right)^2 / a(\phi)\]Here, \(b''(\theta)\) is the second derivative of \(b(\theta)\) with respect to \(\theta\), and \(\left(\frac{d\theta}{d\eta}\right)^2\) captures the transformation from \(\eta\) to \(\theta\).
03

Deduction for inverse weight function

The inverse of the weight function is given by:\[w^{-1} = V(\mu) a(\phi) \left\{\frac{d g(\mu)}{d \mu}\right\}^2\]\(V(\mu)\) is the variance function for the distribution of \(Y\), and \(\frac{d g(\mu)}{d \mu}\) represents the derivative of the link function \(g(\mu)\) with respect to the mean \(\mu\).
04

Determining the adjusted dependent variable

The adjusted dependent variable, \(z\), used in weighted least squares is given by:\[z = \eta + (y - \mu) \frac{d g(\mu)}{d \mu}\]This expression adjusts \(\eta\) by the scaled difference between the observed data \(y\) and its expected value \(\mu\).
05

Identifying formulas for binomial distribution setup

For a binomial distribution \(R = mY\), with \(\pi = \frac{e^{\eta}}{1+e^{\eta}}\), the weight \(w\) and adjusted dependent variable \(z\) take the explicit forms:- Weight:\[w = \pi (1 - \pi) m\]- Adjusted dependent variable:\[z = \eta + (y - \mu) \frac{1}{\mu(1 - \mu)}\]
06

Initial values based on data

Initial values for iterative processes can be set without requiring \(\beta\). For initial calculations, use :\(\mu^1 = y\) and \(\eta^1 = g(y)\), where \(g(\cdot)\) is the link function corresponding to the GLM family.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Iterative Weighted Least Squares
Iterative Weighted Least Squares (IWLS) is an important algorithm used to find maximum likelihood estimates in Generalized Linear Models (GLMs). This method is particularly helpful because GLMs can be complex due to different variance and link functions. The goal of IWLS is to iteratively find estimates for the parameters that improve the fit of the model to the data with each iteration.

The key aspect of IWLS is the use of weights. These weights are derived from the second derivative of the log-likelihood function with respect to the model parameters, which provides a measure of how much the likelihood is expected to change. It's calculated as:
  • Respectively, the weight formula in a generalized linear model is given by \(w = b''(\theta)\left(\frac{d\theta}{d\eta}\right)^2 / a(\phi)\).
  • This expression effectively combines information about the variance and the link function.
This equation plays a crucial role in ensuring that the GLM estimates are optimal at each step, making the overall model robust to variations in the data.

During each iteration, the weights are recalculated, and the model parameters are updated until convergence is achieved. The iterative process allows for adjustment to a variety of data distributions, showcasing the versatility of IWLS.
Variance Function
The variance function, denoted as \(V(\mu)\), in a Generalized Linear Model (GLM) represents how the variance of observations changes as a function of the mean, \(\mu\). It's a critical element because it captures how much the expected variability in the data differs due to intrinsic factors.

Within the framework of GLMs:
  • The variance function is specific to the type of distribution being modeled. For example, in the case of a Poisson distribution, the variance function is equal to the mean, i.e., \(V(\mu) = \mu\). For a binomial distribution, \(V(\mu) = \mu (1 - \mu)\).
  • This function demonstrates how variability is expected to scale with the expected outcomes, which is crucial for accurately assigning weights in the IWLS method.
In practical terms, understanding the variance function aids in setting realistic models that can effectively predict outcomes based on their unique data characteristics.

This is why it is directly incorporated into the inverse weight calculations in the IWLS procedure. The inverse weight \(w^{-1}\) is dependent on \(V(\mu)\), allowing it to reflect the influence of variance directly in the estimation process.
Link Function
The link function in a Generalized Linear Model (GLM) allows for the fitting of diverse types of data by relating the linear predictor to the mean of the distribution function. It is essentially a transformation function that connects the expected value of the response variable to the linear predictors.

In most GLMs:
  • Commonly used link functions include the identity link, log link, and logit link. For example, in a binomial distribution, the logit function \(g(\mu) = \log\left(\frac{\mu}{1-\mu}\right)\) is typically used, linking the probability of success to the predictor.
  • The choice of link function can significantly affect the interpretation of the Regression coefficients, providing linear formats where necessary for analytical clarity.

A critical relationship involving the link function is its derivative \(\frac{d g(\mu)}{d \mu}\) as used in weight and adjusted dependent variable calculations. This derivative helps convert differences between observed and mean values into the linear predictor's scale, adjusting the fit of the model.
Consequently, the flexibility offered by link functions enables GLMs to accommodate a wide range of statistical data distributions.
Binomial Distribution
In the context of Generalized Linear Models (GLMs), understanding the binomial distribution is pivotal when dealing with binary or proportion data. The binomial distribution is often applied in scenarios where each observation represents a number of successes over several trials.

Important aspects include:
  • A binomial distribution takes two parameters: \(n\) (number of trials) and \(\pi\) (probability of success per trial).
  • In GLMs, particularly when using a logit link, the probability \(\pi\) is modeled as \(\pi = \frac{e^{\eta}}{1+e^{\eta}}\), where \(\eta\) is the linear predictor.
For instance, when considering a binomial setup such as \(R = mY\), where \(m\) is a known number of trials, the weight can be explicitly formulated as \(w = \pi (1-\pi) m\). This weight is critical for the IWLS refinement process.
The binomial distribution's variance function, \(V(\mu) = \mu (1-\mu)\), is integral to understanding the data's spread around its mean.By knowing how the binomial distribution properties interface with GLM frameworks, students can better model response variables constrained by two outcomes and achieve more accurate predictions.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Consider a linear smoother with \(n \times n\) smoothing matrix \(S_{h}\), so \(\widehat{g}=S_{h} y\), and show that the function \(a_{j}(u)\) giving the fitted value at \(x_{j}\) as a function of the response \(u\) there satisfies $$ a_{j}(u)= \begin{cases}\widehat{g}\left(x_{j}\right), & u=y_{j} \\\ \widehat{g}_{-j}\left(x_{j}\right), & u=\widehat{g}_{-j}\left(x_{j}\right)\end{cases} $$ Explain why this implies that \(S_{j j}(h)\left\\{y_{j}-\widehat{g}_{-j}\left(x_{j}\right)\right\\}=\widehat{g}\left(x_{j}\right)-\widehat{g}_{-j}\left(x_{j}\right)\), and hence obtain \((10.42)\)

Data \(y_{1}, \ldots, y_{n}\) are assumed to follow a binary logistic model in which \(y_{j}\) takes value 1 with probability \(\pi_{j}=\exp \left(x_{j}^{\mathrm{T}} \beta\right) /\left\\{1+\exp \left(x_{j}^{\mathrm{T}} \beta\right)\right\\}\) and value 0 otherwise, for \(j=1, \ldots, n\). (a) Show that the deviance for a model with fitted probabilities \(\widehat{\pi}_{j}\) can be written as $$ D=-2\left\\{y^{\mathrm{T}} X \widehat{\beta}+\sum_{j=1}^{n} \log \left(1-\hat{\pi}_{j}\right)\right\\} $$ and that the likelihood equation is \(X^{\mathrm{T}} y=X^{\mathrm{T}} \widehat{\pi}\). Hence show that the deviance is a function of the \(\widehat{\pi}_{j}\) alone. (b) If \(\pi_{1}=\cdots=\pi_{n}=\pi\), then show that \(\widehat{\pi}=\bar{y}\), and verify that $$ D=-2 n\\{\bar{y} \log \bar{y}+(1-\bar{y}) \log (1-\bar{y})\\} $$ Comment on the implications for using \(D\) to measure the discrepancy between the data and fitted model. (c) In (b), show that Pearson's statistic (10.21) is identically equal to \(n\). Comment.

For a \(2 \times 2\) contingency table with probabilities $$ \begin{array}{cc} \pi_{00} & \pi_{01} \\ \pi_{10} & \pi_{11} \end{array} $$ the maximal log-linear model may be written as $$ \begin{array}{ll} \eta_{00}=\alpha+\beta+\gamma+(\beta \gamma), & \eta_{01}=\alpha+\beta-\gamma-(\beta \gamma) \\ \eta_{10}=\alpha-\beta+\gamma-(\beta \gamma), & \eta_{11}=\alpha-\beta-\gamma+(\beta \gamma) \end{array} $$ where \(\eta_{j k}=\log \mathrm{E}\left(Y_{j k}\right)=\log \left(m \pi_{j k}\right)\) and \(m=\sum_{j, k} y_{j k} .\) Show that the 'interaction'term \((\beta \gamma)\) may be written \((\beta \gamma)=\frac{1}{4} \log \Delta\), where \(\Delta\) is the odds ratio \(\left(\pi_{00} \pi_{11}\right) /\left(\pi_{01} \pi_{10}\right)\), so that \((\beta \gamma)=0\) is equivalent to \(\Delta=1\)

Two individuals with cumulative hazard functions \(u H_{1}\left(y_{1}\right)\) and \(u H_{2}\left(y_{2}\right)\) are independent conditional on the value \(u\) of a frailty \(U\) whose density is \(f(u)\) (a) For this shared frailty model, show that $$ \mathcal{F}\left(y_{1}, y_{2}\right)=\operatorname{Pr}\left(Y_{1}>y_{1}, Y_{2}>y_{2}\right)=\int_{0}^{\infty} \exp \left\\{-u H_{1}\left(y_{1}\right)-u H_{2}\left(y_{2}\right)\right\\} f(u) d u $$ If \(f(u)=\lambda^{\alpha} u^{\alpha-1} \exp (-\lambda u) / \Gamma(\alpha)\), for \(u>0\) is a gamma density, then show that $$ \mathcal{F}\left(y_{1}, y_{2}\right)=\frac{\lambda^{\alpha}}{\left\\{\lambda+H_{1}\left(y_{1}\right)+H_{2}\left(y_{2}\right)\right\\}^{\alpha}}, \quad y_{1}, y_{2}>0 $$ and deduce that in terms of the marginal survivor functions \(\mathcal{F}_{1}\left(y_{1}\right)\) and \(\mathcal{F}_{2}\left(y_{2}\right)\) of \(Y_{1}\) and \(Y_{2}\) $$ \mathcal{F}\left(y_{1}, y_{2}\right)=\left\\{\mathcal{F}_{1}\left(y_{1}\right)^{-1 / \alpha}+\mathcal{F}_{2}\left(y_{2}\right)^{-1 / \alpha}-1\right\\}^{-\alpha}, \quad y_{1}, y_{2}>0 $$ What happens to this joint survivor function as \(\alpha \rightarrow \infty\) ? (b) Find the likelihood contributions when both individuals are observed to fail, when one is censored, and when both are censored. (c) Extend this to \(k\) individuals with parametric regression models for survival.

The rate of growth of an epidemic such as AIDS for a large population can be estimated fairly accurately and treated as a known function \(g(t)\) of time \(t\). In a smaller area where few cases have been observed the rate is hard to estimate because data are scarce. However predictions of the numbers of future cases in such an area must be made in order to allocate resources such as hospital beds. A simple assumption is that cases in the area arise in a non- homogeneous Poisson process with rate \(\lambda g(t)\), for which the mean number of cases in period \(\left(t_{1}, t_{2}\right)\) is \(\lambda \int_{t_{1}}^{t_{2}} g(t) d t\). Suppose that \(N_{1}=n_{1}\) individuals with the disease have been observed in the period \((-\infty, 0)\), and that predictions are required for the number \(N_{2}\), of cases to be observed in a future period \(\left(t_{1}, t_{2}\right)\). (a) Find the conditional distribution of \(N_{2}\) given \(N_{1}+N_{2}\), and show it to be free of \(\lambda\). Deduce that a \((1-2 \alpha)\) prediction interval \(\left(n_{-}, n_{+}\right)\)for \(N_{2}\) is found by solving approximately the equations $$ \begin{aligned} &\alpha=\operatorname{Pr}\left(N_{2} \leq n_{-} \mid N_{1}+N_{2}=n_{1}+n_{-}\right) \\ &\alpha=\operatorname{Pr}\left(N_{2} \geq n_{+} \mid N_{1}+N_{2}=n_{1}+n_{+}\right) \end{aligned} $$ (b) Use a normal approximation to the conditional distribution in (a) to show that for moderate to large \(n_{1}, n_{-}\)and \(n_{+}\)are the solutions to the quadratic equation $$ (1-p)^{2} n^{2}+p(p-1)\left(2 n_{1}+z_{\alpha}^{2}\right) n+n_{1} p\left\\{n_{1} p-(1-p) z_{\alpha}^{2}\right\\}=0 $$ where \(\Phi\left(z_{\alpha}\right)=\alpha\) and $$ p=\int_{t_{1}}^{t_{2}} g(t) d t /\left\\{\int_{t_{1}}^{t_{2}} g(t) d t+\int_{-\infty}^{0} g(t) d t\right\\} $$ (c) Find approximate \(0.90\) prediction intervals for the special case where \(g(t)=2^{t / 2}\), so that the doubling time for the epidemic is two years, \(n_{1}=10\) cases have been observed until time 0 , and \(t_{1}=0, t_{2}=1\) (next year) (Cox and Davison, 1989).

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free