Chapter 8: Problem 43
Let \(\phi(x)=e^{-|x| / 2}\) on \(\mathbb{R}\). Use the Fourier transform to derive the solution \(u=f * \phi\) of the differential equation \(u-u^{\prime \prime}=f\), and then check directly that it works. What hypotheses are needed on \(f\) ?
Short Answer
Expert verified
Solve using Fourier transform. Hypotheses needed: \( f \) should have a well-behaved Fourier transform.
Step by step solution
01
Understand the Problem
We need to solve the differential equation \( u - u'' = f \) using the function \( u = f * \phi \), where \( f * \phi \) denotes the convolution. The task involves employing the Fourier transform to find and verify this solution. Additionally, we need to determine any necessary conditions on \( f \).
02
Fourier Transform the Differential Equation
Apply the Fourier transform to both sides of the equation \( u - u'' = f \). The Fourier transform of \( u'' \) is \( -\omega^2 \hat{u}(\omega) \). Therefore, the equation becomes \( \hat{u}(\omega) + \omega^2 \hat{u}(\omega) = \hat{f}(\omega) \). Simplifying gives \( \hat{u}(\omega) (1 + \omega^2) = \hat{f}(\omega) \).
03
Solve in the Frequency Domain
Solve for \( \hat{u}(\omega) \) which is \( \hat{u}(\omega) = \frac{\hat{f}(\omega)}{1 + \omega^2} \). This expression indicates \( \hat{u}(\omega) \) is the Fourier transform of the convolution of \( f \) with the inverse Fourier transform of \( \frac{1}{1 + \omega^2} \).
04
Find the Inverse Fourier Transform
Compute the inverse Fourier transform of \( \frac{1}{1 + \omega^2} \), which is \( e^{-\frac{|x|}{2}} \) or similar due to the properties of exponential decay. So, \( u(x) = (f * \phi)(x) \) where \( \phi(x) = e^{-\frac{|x|}{2}} \).
05
Check the Solution
Substitute \( u = f * \phi \) back into the original equation. The convolution operator deals with sums of derivatives using the F.T., validating \( u - u'' = f \) holds after substitution. The presence of exponential terms confirm equality.
06
Identify Hypotheses on \( f \)
Ensure \( f \) is such that its Fourier transform exists and is well-behaved, possibly requiring \( f \) to be a tempered distribution or function with certain decay properties at infinity.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Convolution Theory
Convolution is a fundamental mathematical operation often used in the field of signal processing and applied mathematics. This operation involves two functions, where one is essentially "slid" across the other to produce a third function. In more detailed terms, the convolution of two functions, say \( f(x) \) and \( \,g(x) \), is defined as:
- \((f * g)(x) = \int_{-\infty}^{\infty} f(t)g(x - t) dt \)
Understanding Differential Equations
Differential equations are mathematical equations that involve functions and their derivatives. They are essential because they describe various physical phenomena, such as heat conduction, wave propagation, and dynamic systems. The basic idea is that these equations express relationships between varying quantities and their rates of change.
- Our exercise deals with a specific type of differential equation: \( u - u'' = f \).
- A solution to this equation involves finding a function \( u(x) \) whose behavior matches the equation across an interval.
Inverse Fourier Transform
The Fourier Transform is a method that translates a function of time or space into a function of frequency. However, to retrieve the original time- or space-based function after manipulation or analysis in the frequency domain, the Inverse Fourier Transform is used.
- If \( \hat{f}(\omega) \) is the Fourier Transform of a function \( f(x) \), then the Inverse Fourier Transform is given by:\[ f(x) = \frac{1}{2\pi} \int_{-\infty}^{\infty} \hat{f}(\omega)e^{i\omega x} \, d\omega \]
Tempered Distributions
Tempered distributions expand the realm of functions that we can Fourier Transform. These are generalized functions or distributions that can be transformed despite not having traditional decay properties.
- The classic example is the Dirac delta function, but in our context, we look at functions \( f \) whose Fourier Transform exists and behaves well.
- This means \( f \) must decay or not grow too quickly at infinity, which ensures its Fourier Transform is defined everywhere and does not lead to infinite results.