Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Suppose \(0

Short Answer

Expert verified
For $q=\infty$, $L^p \not\subset L^\infty$ if sets have arbitrarily small measures, $L^\infty \not\subset L^p$ if sets have arbitrarily large measures.

Step by step solution

01

Problem Interpretation

We need to determine the conditions under which the inclusion \(L^p \subset L^\infty\) or \(L^\infty \subset L^p\) holds or does not hold, extending the logic from the given conditions for \(0<p<q<\infty\) to the case \(q=\infty\).
02

Understanding $L^\infty$ Space

The space \(L^\infty(X)\) consists of essentially bounded functions, where the essential supremum is finite. Functions in \(L^\infty\) can have large measure support but must remain bounded in magnitude.
03

Inclusion Analysis for $L^p \rightarrow L^\infty$

For \(L^p(X) \subset L^\infty(X)\) to hold, functions in \(L^p\) must be essentially bounded. However, \(L^p\) functions can be unbounded, so \(L^p ot\subset L^\infty\) generally holds unless measures of the sets involved are controlled.
04

Conditions Where $L^p(X) \not\subset L^\infty(X)$

If \(X\) contains sets of arbitrarily small positive measure, we can construct functions in \(L^p\) whose \(L^\infty\) norm is infinite, meaning \(L^p ot\subset L^\infty\) for all \(0<p<\infty\) unless the measure space prevents unbounded functions from occurring on small sets.
05

Inclusion Analysis for $L^\infty \rightarrow L^p$

For \(L^\infty(X) \subset L^p(X)\) to hold, the \(L^p\) norm must remain finite for all \(L^\infty\) functions. If \(X\) contains sets of arbitrarily large finite measure, a bounded function with large support leads to an infinite \(L^p\) norm, hence \(L^\infty ot\subset L^p\).
06

Conclusion for $q=\infty$

Thus, when \(q=\infty\), \(L^p ot\subset L^\infty\) if \(X\) contains sets of arbitrarily small positive measure, and \(L^\infty ot\subset L^p\) if \(X\) contains sets of arbitrarily large finite measure.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Measure Theory
Measure theory is a branch of mathematical analysis focused on the study of measures, integrals, and their applications. It provides a framework to measure the size or volume of complex geometrical shapes and functions.

In essence, a measure is a systematic way to assign a number to a subset of a given space, which can be thought of as the 'size' or 'mass' of the subset. This is generalizable to more abstract settings than just length or area.

Some key concepts of measure theory include:
  • Measure Space: Composed of a set, a sigma-algebra of subsets, and a measure function. These are the building blocks where concepts like integration and probability are grounded.
  • Sigma-algebra: Collection of subsets of a given set, closed under complementation and countable unions.
  • Set of Measure Zero: Very small or negligible sets, crucial in the distinction between almost everywhere and everywhere properties in functions.

In the context of Lp spaces and the given exercise, measure theory is used to analyze when and why certain functions belong to certain function spaces depending on the 'fits' of their measures. Understanding measure helps determine the inclusivity and exclusivity of Lp spaces.
Function Spaces
Function spaces are sets of functions with a defined structure that allows for a detailed analysis of their properties. These structures often involve a distance metric or a norm, helping to compare and understand the functions in that space.

Among these, Lp spaces are a vital concept in functional analysis and measure theory. Here, functions are categorized based on the integrability of their absolute value raised to the power p. Specifically, the Lp space is composed of all the functions whose p-th power of the absolute value is integrable.
  • Lp Norm: It is defined for a function \( f \) as \( \left(\int |f|^p d \mu \right)^{1/p} \). This norm induces the structure of Lp spaces, allowing functions therein to be compared.
  • Inner Product Spaces: L2 spaces, a special case, are equipped with an inner product and are pivotal in quantum mechanics and other fields.
  • Completeness: Lp spaces are complete, meaning every Cauchy sequence of functions in these spaces converges to a function within the same space.

Understanding function spaces, particularly Lp spaces, aids in appreciating the complex nature and requirements for functions to belong to such spaces, especially in problems involving integration and measure theory.
Inclusion Property of Spaces
The inclusion property refers to the way one function space might be 'contained' within another. For Lp spaces, this often involves exploring when functions in a more restrictive space are also contained in a larger space. The given exercise outlines conditions for such inclusions.

In the context of the problem, when dealing with function spaces like Lp and Lq (with \( 0 < p < q < \infty \)), we explore whether functions within Lp are also in Lq and vice-versa.
  • Strict Inclusion: Generally, if \( p < q \), Lq is a strictly larger space than Lp. Thus, Lp\( ot\subset \) Lq unless specific conditions are met regarding the measure of the involved sets.
  • Measure Conditions: For inclusion to hold, the measure space X must lack sets of arbitrarily small or arbitrarily large measure, as these sets can create counterexamples where inclusion fails.
  • Converse Inclusion: Conversely, exploring whether Lq\( \subset \)Lp highlights situations where boundedness and measure interplay create overlap between these spaces.
Through this concept, we gain insight into the versatility and limitations of function spaces, guiding the application of functions depending on their integrability and measure distributions.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Suppose \(1 \leq p<\infty\). If \(\left\|f_{n}-f\right\|_{p} \rightarrow 0\), then \(f_{n} \rightarrow f\) in measure, and hence some subsequence converges to \(f\) a.e. On the other hand, if \(f_{n} \rightarrow f\) in measure and \(\left|f_{n}\right| \leq g \in L^{P}\) for all \(n\), then \(\left\|f_{n}-f\right\|_{p} \rightarrow 0\).

If \(f \in\) weak \(L^{p}\) and \(\mu(\\{x: f(x) \neq 0\\})<\infty\), then \(f \in L^{q}\) for all \(qp\).

If \(f\) is absolutely continuous on \([\epsilon, 1]\) for \(0<\epsilon<1\) and \(\int_{0}^{1} x\left|f^{\prime}(x)\right|^{p} d x<\infty\), then \(\lim _{x \rightarrow 0} f(x)\) exists (and is finite) if \(p>2,|f(x)| /|\log x|^{1 / 2} \rightarrow 0\) as \(x \rightarrow 0\) if \(p=2\), and \(|f(x)| / x^{1-(2 / p)} \rightarrow 0\) as \(x \rightarrow 0\) if \(p<2\).

Suppose that \(K\) is a nonnegative measurable function on \((0, \infty)\) such that \(\int_{0}^{\infty} K(x) x^{s-1} d x=\phi(s)<\infty\) for \(0

(The Vitali Convergence Theorem) Suppose \(1 \leq p<\infty\) and \(\left\\{f_{n}\right\\}_{1}^{\infty} \subset L^{p}\). In order for \(\left\\{f_{n}\right\\}\) to be Cauchy in the \(L^{p}\) norm it is necessary and sufficient for the following three conditions to hold: (i) \(\left\\{f_{n}\right\\}\) is Cauchy in measure; (ii) the sequence \(\left\\{\left|f_{n}\right|^{P}\right\\}\) is uniformly integrable (see Exercise 11 in \(\S 3.2\) ); and (iii) for every \(\in>0\) there exists \(E \subset X\) such that \(\mu(E)<\infty\) and \(\int_{E^{c}}\left|f_{n}\right|^{p}<\epsilon\) for all \(n\). (To prove the sufficiency: Given \(\epsilon>0\), let \(E\) be as in (iii), and let \(A_{\operatorname{mn}}=\\{x \in E\) : \(\left.\left|f_{m}(x)-f_{n}(x)\right| \geq \epsilon\right\\}\). Then the integrals of \(\left|f_{n}-f_{m}\right|^{p}\) over \(E \backslash A_{m n}, A_{m n}\), and \(E^{c}\) are small when \(m\) and \(n\) are large - for three different reasons.)

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free