Chapter 1: Problem 5
If \(\mathcal{M}\) is the \(\sigma\)-algebra generated by \(\mathcal{\varepsilon}\), then \(\mathcal{M}\) is the union of the \(\sigma\)-algebras generated by \(\mathcal{F}\) as \(\mathcal{F}\) ranges over all countable subsets of \(\mathcal{E}\). (Hint: Show that the latter object is a \(\sigma\)-algebra.)
Short Answer
Expert verified
\( \mathcal{M} \) is the union of \( \sigma\)-algebras generated by countable subsets of \( \mathcal{E} \).
Step by step solution
01
Understand the Problem Statement
We are given that \( \mathcal{M} \) is the \( \sigma\)-algebra generated by a family \( \mathcal{E} \). We need to show that \( \mathcal{M} \) is the union of all \( \sigma\)-algebras generated by countable subsets of \( \mathcal{E} \).
02
Identify Properties of \( \sigma\)-Algebras
A \( \sigma\)-algebra \( \mathcal{A} \) over a set \( X \) must be closed under countable unions, countable intersections, and complementation, containing the empty set. The \( \sigma\)-algebra generated by \( \mathcal{E} \), denoted as \( \sigma(\mathcal{E}) \), is the smallest \( \sigma\)-algebra containing \( \mathcal{E} \).
03
Construct \( \sigma \)-Algebra from Countable Subsets
Consider all possible countable subsets \( \mathcal{F} \) of \( \mathcal{E} \). For each countable subset \( \mathcal{F} \), generate the \( \sigma\)-algebra \( \sigma(\mathcal{F}) \). Each of these \( \sigma\)-algebras is closed under the formation rules of a \( \sigma\)-algebra.
04
Form the Union of \( \sigma \)-Algebras
Form the union of all \( \sigma(\mathcal{F}) \) where \( \mathcal{F} \) is a countable subset of \( \mathcal{E} \). Denote this union as \( \bigcup_{\mathcal{F} \subseteq \mathcal{E}, \mathcal{F} \text{ countable}} \sigma(\mathcal{F}) \).
05
Verify \( \mathcal{M} \) as a \( \sigma \)-Algebra
Show that \( \bigcup_{\mathcal{F} \subseteq \mathcal{E}, \mathcal{F} \text{ countable}} \sigma(\mathcal{F}) \) is indeed a \( \sigma\)-algebra. Since \( \mathcal{F} \) is countable, \( \sigma(\mathcal{F}) \) will be closed under the rules for formations of a \( \sigma\)-algebra. Consequently, unioning all \( \sigma(\mathcal{F}) \) will not break these properties and thus it forms a \( \sigma\)-algebra.
06
Conclude and Simplify the Required Equation
Conclude that \( \mathcal{M} = \bigcup_{\mathcal{F} \subseteq \mathcal{E}, \mathcal{F} \text{ countable}} \sigma(\mathcal{F}) \). Therefore, \( \mathcal{M} \) can be viewed as the union of \( \sigma\)-algebras generated from countable subsets of \( \mathcal{E} \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
generated σ-algebra
In probability and measure theory, a \( \sigma \)-algebra is a mathematical structure that helps in understanding collections of subsets. These \( \sigma \)-algebras are essential for defining measures, which in turn help in formulating probability. But what is a 'generated \( \sigma \)-algebra'?
A generated \( \sigma \)-algebra, denoted as \( \sigma(\mathcal{E}) \), is the smallest \( \sigma \)-algebra containing a given collection of subsets \( \mathcal{E} \). This means any other \( \sigma \)-algebra containing \( \mathcal{E} \) must also contain this generated \( \sigma \)-algebra.
To generate this smallest \( \sigma \)-algebra, we must ensure it is closed under certain operations, such as:
A generated \( \sigma \)-algebra, denoted as \( \sigma(\mathcal{E}) \), is the smallest \( \sigma \)-algebra containing a given collection of subsets \( \mathcal{E} \). This means any other \( \sigma \)-algebra containing \( \mathcal{E} \) must also contain this generated \( \sigma \)-algebra.
To generate this smallest \( \sigma \)-algebra, we must ensure it is closed under certain operations, such as:
- Countable unions: Combining infinitely many subsets from the collection.
- Countable intersections: Finding common elements across an infinite number of subsets.
- Taking complements: Finding what is not included in each subset.
countable subsets
Many times in mathematics, dealing with infinite collections can be challenging. Yet, countable subsets make this easier. A countable set refers to a set that can be mapped to natural numbers neatly.
Countable subsets are essential in constructing \( \sigma \)-algebras because, often, infinite operations like unions and intersections are performed over them. This is particularly important when discussing the union of \( \sigma \)-algebras formed by countable subsets of a set \( \mathcal{E} \).
Countable subsets are essential in constructing \( \sigma \)-algebras because, often, infinite operations like unions and intersections are performed over them. This is particularly important when discussing the union of \( \sigma \)-algebras formed by countable subsets of a set \( \mathcal{E} \).
- If a set is countable, like natural numbers or even a subset of real numbers, then it's manageable via standard mathematical tools.
- Even if a whole set is uncountable, such as all real numbers, breaking it down into countable subsets allows us to work with parts that can be easier to handle.
properties of σ-algebra
A \( \sigma \)-algebra is indispensable in fields like measure theory, which supports probability and integration theories. Its defining properties ensure reliability and consistency in mathematical operations:
- Closed under countable unions: If you take an infinite union of sets in a \( \sigma \)-algebra, the result is also in the same \( \sigma \)-algebra.
- Closed under countable intersections: Any infinite intersection of sets within the \( \sigma \)-algebra remains within it as well.
- Closed under complements: If a set is in the \( \sigma \)-algebra, its complement is also included. This means if one set belongs, so does everything outside it in the universe considered.
- Contains the empty set: By definition, every \( \sigma \)-algebra will include the empty set, as it acts as a basic element of the space.