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Let \(\mathcal{A} \subset \mathcal{P}(X)\) be an algebra, \(\mathcal{A}_{\sigma}\) the collection of countable unions of sets in \(\mathcal{A}\), and \(\mathcal{A}_{\sigma \sigma}\) the collection of countable intersections of sets in \(\mathcal{A}_{\sigma}\). Let \(\mu_{0}\) be a premeasure on \(\mathcal{A}\) and \(\mu^{*}\) the induced outer measure. a. For any \(E \subset X\) and \(\epsilon>0\) there exists \(A \in \mathcal{A}_{\sigma}\) with \(E \subset A\) and \(\mu^{*}(A) \leq\) \(\mu^{*}(E)+\epsilon\). b. If \(\mu^{*}(E)<\infty\), then \(E\) is \(\mu^{*}\)-measurable iff there exists \(B \in A_{\sigma \delta}\) with \(E \subset B\) and \(\mu^{*}(B \backslash E)=0\). c. If \(\mu_{0}\) is \(\sigma\)-finite, the restriction \(\mu^{*}(E)<\infty\) in (b) is superfluous.

Short Answer

Expert verified
Part a: Use countable unions. Part b: Measurability involves a zero-measure difference. Part c: \(\sigma\)-finiteness removes the finiteness restriction.

Step by step solution

01

Understanding the Problem

We need to show different properties related to the induced outer measure \(\mu^{*}\) from a premeasure \(\mu_{0}\) on an algebra \(\mathcal{A}\). Our task includes proving statements about sets \(E\) in terms of their inclusion in specific collections, \(\mathcal{A}_{\sigma}\) for part (a), measurability conditions in terms of \(\mathcal{A}_{\sigma\delta}\) for part (b), and considerational subtleties around \(\sigma\)-finiteness for part (c).
02

Proving Part (a)

The goal is to show that for any \(E \subset X\) and \(\epsilon>0\), there exists \(A \in \mathcal{A}_{\sigma}\) with \(E \subset A\) and \(\mu^{*}(A) \leq \mu^{*}(E)+\epsilon\). This is a standard result about outer measures where the set \(A\) can be constructed as a countable union of sets from \(\mathcal{A}\) whose measure approximates that of \(E\). This follows from the definition of \(\mu^{*}(E)\) as the infimum over all covers of \(E\) from \(\mathcal{A}\).
03

Proving Part (b)

We need to show that if \(\mu^{*}(E)<\infty\), then \(E\) is \(\mu^{*}\)-measurable if and only if there exists \(B \in \mathcal{A}_{\sigma\delta}\) such that \(E \subset B\) and \(\mu^{*}(B \backslash E)=0\). This uses the definition of \(\mu^{*}\)-measurability, where a set \(E\) is \(\mu^{*}\)-measurable if for any \(S\), \(\mu^{*}(S) = \mu^{*}(S \cap E) + \mu^{*}(S \cap E^c)\). The construction of \(B\) leverages \(\mathcal{A}_{\sigma\delta}\)'s closure properties.
04

Proving Part (c)

In this part, we demonstrate that if \(\mu_{0}\) is \(\sigma\)-finite, the condition \(\mu^{*}(E)<\infty\) in part (b) is not needed. \(\sigma\)-finiteness implies there exists a countable cover of \(X\) by sets with finite measure, simplifying measurability considerations and allowing \(E\) to be \(\mu^{*}\)-measurable without restriction to finiteness.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Algebra
In measure theory, an algebra is a collection of sets closed under the operations of union, intersection, and complement relative to a universal set. Consider it a well-behaved set system that ensures each operation results in another set in the same collection. A universal set here is a set containing all objects of interest in a particular discussion.
  • Union: If sets A and B are in the algebra, then A ∪ B is also in it.
  • Intersection: If sets A and B are in the algebra, A ∩ B also belongs to the algebra.
  • Complement: If set A is in the algebra, then the complement of A, relative to the universal set, is in the algebra.
An algebra is a foundational structure that provides a framework on which premeasures and, subsequently, measures can be defined.
Premeasure
A premeasure is a function defined on an algebra that helps construct a measure. It provides a way to assign "size" or "volume" to sets in an algebra. While not yet a full measure, it offers the building blocks necessary to create one.
Let's break this down:
  • A premeasure \( \mu_{0} \) is defined on the algebra \( \mathcal{A} \).
  • \( \mu_{0} \) must be non-negative and include a measure of zero for the empty set: \( \mu_{0}(\emptyset) = 0 \).
  • It is finitely additive, meaning if two disjoint sets \( A \) and \( B \) are in \( \mathcal{A} \), then \( \mu_{0}(A \cup B) = \mu_{0}(A) + \mu_{0}(B) \).
The goal of premeasures is to enable the construction of outer measures, thus preparing the landscape for defining full measures.
Sigma-finiteness
Sigma-finiteness is a property of premeasures or measures that relates to their manageability. A premeasure \( \mu_{0} \) is said to be \( \sigma \)-finite if the whole space can be covered by a countable union of sets with finite premeasure.
Why is this important?
  • Ensures tractability: It makes analyzing infinite spaces feasible by breaking them into manageable parts.
  • Extends measurability: When \( \mu_{0} \) is \( \sigma \)-finite, assumptions of finiteness in proofs can often be removed.
This property can simplify complex measure-theoretic arguments by allowing more flexibility in how sets and their measures are considered.
Measurability
Measurability in the context of outer measures, like \( \mu^{*} \), refers to the idea of a set being "well-behaved" with regard to that measure. A set is \( \mu^{*} \)-measurable if certain criteria are met that facilitate consistent calculations with it.
Here's how it works:
  • Given a set \( E \), it is \( \mu^{*} \)-measurable if for any other set \( S \), the outer measure satisfies \( \mu^{*}(S) = \mu^{*}(S \cap E) + \mu^{*}(S \cap E^c) \).
  • This condition ensures that measuring the part of \( S \) inside \( E \) and the part outside \( E \) gives the complete measure when combined.
Establishing measurability often involves finding a "nice" cover, such as a set \( B \) whose difference from \( E \) has negligible measure, making calculations straightforward and consistent.

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Most popular questions from this chapter

If \(\mu^{*}\) is an outer measure on \(X\) and \(\left\\{A_{j}\right\\}_{1}^{\infty}\) is a sequence of disjoint \(\mu^{*}\) measurable sets, then \(\mu^{*}\left(E \cap\left(\bigcup_{1}^{\infty} A_{j}\right)\right)=\sum_{1}^{\infty} \mu^{*}\left(E \cap A_{j}\right)\) for any \(E \subset X .\)

A family of sets \(\mathcal{R} \subset \mathcal{P}(X)\) is called a ring if it is closed under finite unions and differences (i.e., if \(E_{1}, \ldots, E_{n} \in \mathcal{R}\), then \(\bigcup_{1}^{n} E_{j} \in \mathcal{R}\), and if \(E, F \in \mathcal{R}\), then \(E \backslash F \in \mathcal{R}\) ). A ring that is closed under countable unions is called a \(\sigma\)-ring. a. Rings (resp. \(\sigma\)-rings) are closed under finite (resp. countable) intersections. b. If \(\mathcal{R}\) is a ring (resp. \(\sigma\)-ring), then \(\mathcal{R}\) is an algebra (resp. \(\sigma\)-algebra) iff \(X \in \mathcal{R}\). c. If \(\mathcal{R}\) is a \(\sigma\)-ring, then \(\left\\{E \subset X: E \in \mathcal{R}\right.\) or \(\left.E^{c} \in \mathcal{R}\right\\}\) is a \(\sigma\)-algebra. d. If \(\mathcal{R}\) is a \(\sigma\)-ring, then \(\\{E \subset X: E \cap F \in \mathcal{R}\) for all \(F \in \mathcal{R}\\}\) is a \(\sigma\)-algebra.

Let \(\mu^{*}\) be an outer measure induced from a premeasure and \(\bar{\mu}\) the restriction of \(\mu^{*}\) to the \(\mu^{*}\)-measurable sets. Then \(\bar{\mu}\) is saturated.

Given a measure space \((X, \mathcal{M}, \mu)\) and \(E \in \mathcal{M}\), define \(\mu_{E}(\mathcal{A})=\mu(A \cap E)\) for \(A \in \mathcal{M}\). Then \(\mu_{E}\) is a measure.

If \(\mathcal{M}\) is the \(\sigma\)-algebra generated by \(\mathcal{\varepsilon}\), then \(\mathcal{M}\) is the union of the \(\sigma\)-algebras generated by \(\mathcal{F}\) as \(\mathcal{F}\) ranges over all countable subsets of \(\mathcal{E}\). (Hint: Show that the latter object is a \(\sigma\)-algebra.)

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