Chapter 8: Problem 5
A can do a piece of work in 10 days, \(B\) can do it in 15 days working together they can finish the work in : (a) 9 (b) 8 (c) 10 (d) 6
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\(A\) and \(B\) can do a piece of work in 12 days, \(B\) and \(C\) in 15 days \(\mathrm{C}\) and \(\mathrm{A}\) in 20 days. In how many days can \(\mathrm{C}\) alone do it? (a) 60 (b) 50 (c) 25 (d) 24
\(C\) takes twice the number of days to do a piece of work than \(A\) takes. \(A\) and \(B\) together can do it in 6 days while \(B\) and \(C\) can do it in 10 days. In how many days \(A\) alone can do the work? (a) 60 (b) 30 (c) 6 (d) \(7.5\)
\(A\) and \(B\) can do a piece of work in 8 days, \(B\) and \(C\) can do the work in 12 days and \(A\) and \(C\) complete it in 8 days. In same work days \(A, B\) and \(C\) can complete the whole work, how many day working together? (a) 4 (b) 6 (c) 12 (d) 9
\(A\) and \(B\) can complete a task in 30 days when working together after \(A\) and \(B\) have been working together for 11 days, \(B\) is called away and \(A\), all by himself completes the task in the next 28 days. Had \(A\) been working alone, the number of days taken by him to complete the task would have been : (a) \(33 \frac{3}{19}\) (b) \(19 \frac{6}{25}\) (c) \(44 \frac{4}{19}\) (d) none of these
Fatima and Zahira can do a piece of work in 12 days and 15 days respectively. If they work for alternate day and Fatima starts the work first, then in how many days the work will be completed? \(\begin{array}{ll}\text { (a) } 12 \frac{1}{5} & \text { (b) } 13 \frac{1}{4}\end{array}\) (c) \(13 \frac{1}{5}\) (d) 15
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