Chapter 11: Problem 32
If tan \(\theta=2-\sqrt{3}\), then \(\tan (90-\theta)\) is equal to : (a) \(2+\sqrt{3}\) (b) \(2-\sqrt{3}\) (c) \(3+\sqrt{2}\) (d) \(3-\sqrt{2}\)
Short Answer
Expert verified
(a) \(2+\sqrt{3}\)
Step by step solution
01
Given value
We are given that \(\tan \theta = 2 - \sqrt{3}\).
02
Find the value of \(\cot\theta\)
Recall that \(\cot\theta\) is the reciprocal of \(\tan\theta\). Therefore, we can find \(\cot\theta\) as follows:
$$\cot\theta = \frac{1}{\tan\theta} = \frac{1}{2-\sqrt {3}}$$
Now, we rationalize the denominator by multiplying the numerator and denominator by the conjugate of the denominator:
$$\cot\theta = \frac{1}{2-\sqrt {3}} \times \frac{2+\sqrt {3}}{2+\sqrt {3}}$$
$$\cot\theta = \frac{2+\sqrt {3}}{(2-\sqrt {3})(2+\sqrt {3})}$$
Since \((a-b)(a+b) = a^2 - b^2\), we can simplify the denominator:
$$\cot\theta = \frac{2+\sqrt {3}}{(2^2 - (\sqrt {3})^2)}$$
$$\cot\theta = \frac{2+\sqrt {3}}{4 - 3}$$
$$\cot\theta = 2+\sqrt {3}$$
03
Use the identity \(\tan(90 - x) = \cot x\) to find \(\tan(90-\theta)\)
Since we now have the value of \(\cot\theta\), we can use the identity \(\tan(90 - x) = \cot x\) to find \(\tan(90-\theta)\):
$$\tan(90-\theta) = \cot\theta = 2+\sqrt {3}$$
So, the correct answer choice is:
(a) \(2+\sqrt{3}\)
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with Vaia!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Tangent Function
The tangent function is one of the fundamental trigonometric functions defined for an angle in a right-angled triangle. It represents the ratio of the length of the opposite side to the length of the adjacent side. If we denote an angle by \(\theta\), then:
Besides its geometric definition, the tangent function is also understood in the context of the unit circle. Here, it is the y-coordinate of the point where the terminal side of an angle intersects a line tangent to the circle at \((1,0)\). For all values of \(\theta\), tangent can be expressed as:
- \( \tan \theta = \frac{\text{Opposite}}{\text{Adjacent}} \)
Besides its geometric definition, the tangent function is also understood in the context of the unit circle. Here, it is the y-coordinate of the point where the terminal side of an angle intersects a line tangent to the circle at \((1,0)\). For all values of \(\theta\), tangent can be expressed as:
- \(\tan \theta = \frac{\sin \theta}{\cos \theta}\)
Cotangent Function
The cotangent function is closely related to the tangent function and is defined as the reciprocal of the tangent function. For an angle \(\theta\), this means:
In terms of a right-angled triangle, cotangent also has a simple interpretation. It represents the ratio of the length of the adjacent side to the length of the opposite side:
Another way to express cotangent is using sine and cosine:
- \( \cot \theta = \frac{1}{\tan \theta} \)
In terms of a right-angled triangle, cotangent also has a simple interpretation. It represents the ratio of the length of the adjacent side to the length of the opposite side:
- \( \cot \theta = \frac{\text{Adjacent}}{\text{Opposite}} \)
Another way to express cotangent is using sine and cosine:
- \( \cot \theta = \frac{\cos \theta}{\sin \theta} \)
Trigonometric Identities
Trigonometric identities are mathematical equations that involve trigonometric functions and hold true for all values in their domains. They are vital tools in simplifying complex trigonometric expressions and solving equations.
One important identity involving the tangent and cotangent functions is:
Understanding identities like these allows for quick calculations without direct recourse to lengthy geometric reasoning.
Other fundamental trigonometric identities include:
One important identity involving the tangent and cotangent functions is:
- \( \tan(90^\circ - \theta) = \cot \theta \)
Understanding identities like these allows for quick calculations without direct recourse to lengthy geometric reasoning.
Other fundamental trigonometric identities include:
- The Pythagorean identity: \( \sin^2 \theta + \cos^2 \theta = 1 \)
- Sum and difference formulas, such as \( \tan(a \pm b) = \frac{\tan a \pm \tan b}{1 \mp \tan a \tan b} \)