Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

In a famous experiment carried out in 1882, Michelson,and Newcomb obtained 66 observations on the time it took for light to travel between two locations in Washington, D.C. A few of the measurements(coded in a certain manner) were 31, 23, 32, 36, 22, 26, 27, and 31.

a. Why are these measurements not identical?

b. Is this an enumerative study? Why or why not?

Short Answer

Expert verified

a.Nonidenticalmeasurements are because of the errors such as recording error, measurement error etc.

b.The study is not enumerative.

Step by step solution

01

Given information

The number of observations Michelson and Newcomb obtained on the time it took for the light to travel between two locations is 66.

A few measurements that were coded in a certain manner are 31,23,32,36,22,26,27, and 31.

02

Explain the reason for nonidentical measurements.

a.

The provided measurements are nonidentical because of certain errorssuch as measurement error, changing of the environment when recoding the time, recoding error etc.

03

Check whether the study is enumerative.

b.

The study is said to beenumerativeif the population from which the sample is selected is finite and identifiable.

In the provided scenario, the population data is not provided. Therefore, it is not an enumerative study.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The weekly demand for propane gas (in \({\rm{1000s}}\) of gallons) from a particular facility is an \({\rm{rv}}\) \({\rm{X}}\) with pdf

\({\rm{f(x) = }}\left\{ {\begin{array}{*{20}{c}}{{\rm{2}}\left( {{\rm{1 - }}\frac{{\rm{1}}}{{{{\rm{x}}^{\rm{2}}}}}} \right)}&{{\rm{1}} \le {\rm{x}} \le {\rm{2}}}\\{\rm{0}}&{{\rm{ otherwise }}}\end{array}} \right.\)

a. Compute the cdf of \({\rm{X}}\).

b. Obtain an expression for the \({\rm{(100p)th}}\) percentile. What is the value of \({\rm{\tilde \mu }}\)?

c. Compute \({\rm{E(X)}}\) and \({\rm{V(X)}}\).

d. If \({\rm{1}}{\rm{.5}}\) thousand gallons are in stock at the beginning of the week and no new supply is due in during the week, how much of the \({\rm{1}}{\rm{.5}}\) thousand gallons is expected to be left at the end of the week? (Hint: Let \({\rm{h(x) = }}\) amount left when demand \({\rm{ = x}}\).)

Let \({\bar x_n}\) and \(s_n^2\) denote the sample mean and variance for the sample \({x_1},{x_2},...,{x_n}\) and let \({\bar x_{n + 1}}\) and \(s_{n + 1}^2\) denote these quantities when an additional observation \({x_{n + 1}}\) is added to the sample.

a. Show how\({\bar x_{n + 1}}\)can be computed from\({\bar x_n}\)and\({x_{n + 1}}\).

b. Show that

\(ns_{n + 1}^2 = \left( {n - 1} \right)s_n^2 + \frac{n}{{n + 1}}{\left( {{x_{n + 1}} - {{\bar x}_n}} \right)^2}\)

so that\(s_{n + 1}^2\)can be computed from\({x_{n + 1}}\),\({\bar x_n}\), and\(s_n^2\).

c. Suppose that a sample of 15 strands of drapery yarn has resulted in a sample mean thread elongation of 12.58 mm and a sample standard deviation of .512 mm. A 16th strand results in an elongation value of 11.8. What are the values of the sample mean and sample standard deviation for all 16 elongation observations?

Give one possible sample of size 4 from each of the following

populations:

a. All daily newspapers published in the United States

b. All companies listed on the New York Stock Exchange

c. All students at your college or university

d. All grade point averages of students at your college or university

The article โ€œStatistical Modeling of the Time Courseof Tantrum Angerโ€ (Annals of Applied Stats, 2009:1013โ€“1034) discussed how anger intensity in childrenโ€™s tantrums could be related to tantrumduration as well as behavioral indicators such asshouting, stamping, and pushing or pulling. The followingfrequency distribution was given (and also

the corresponding histogram):

0-<2: 136 2-<4: 92 4-<11: 71

11-<20: 26 20-<30: 7 30-<40: 3

Draw the histogram and then comment on any interesting features.

Let \({\rm{X}}\) be the total medical expenses (in \({\rm{1000}}\) s of dollars) incurred by a particular individual during a given year. Although \({\rm{X}}\) is a discrete random variable, suppose its distribution is quite well approximated by a continuous distribution with pdf \({\rm{f(x) = k(1 + x/2}}{\rm{.5}}{{\rm{)}}^{{\rm{ - 7}}}}\) for.

a. What is the value of\({\rm{k}}\)?

b. Graph the pdf of \({\rm{X}}\).

c. What are the expected value and standard deviation of total medical expenses?

d. This individual is covered by an insurance plan that entails a \({\rm{\$ 500}}\) deductible provision (so the first \({\rm{\$ 500}}\) worth of expenses are paid by the individual). Then the plan will pay \({\rm{80\% }}\) of any additional expenses exceeding \({\rm{\$ 500}}\), and the maximum payment by the individual (including the deductible amount) is\({\rm{\$ 2500}}\). Let \({\rm{Y}}\) denote the amount of this individual's medical expenses paid by the insurance company. What is the expected value of\({\rm{Y}}\)?

(Hint: First figure out what value of \({\rm{X}}\) corresponds to the maximum out-of-pocket expense of \({\rm{\$ 2500}}\). Then write an expression for \({\rm{Y}}\) as a function of \({\rm{X}}\) (which involves several different pieces) and calculate the expected value of this function.)

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free