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Suppose that an electronic system contains n components that function independently of each other, and suppose that these components are connected in series, as defined in Exercise 5 of Sec. 3.7. Suppose also that each component will function properly for a certain number of periods and then will fail. Finally, suppose that for i =1,...,n, the number of periods for which component i will function properly is a discrete random variable having a geometric distribution with parameter \({p_i}\). Determine the distribution of the number of periods for which the system will function properly.

Short Answer

Expert verified

Distribution of the number of periods for which the system will function properly is geometric distribution with \(p = 1 - \prod\limits_{i = 1}^n {\left( {1 - {p_i}} \right)} \).

Step by step solution

01

Given information

An Electronic system contain n components that function independently of each other.

These components are connected in series.

02

Calculating the distribution.

Since the components are connected in series, the system will function properly only as long as every component function properly.

Let\({X_i}\)be the number of periods that component ifunctions properly.

For\(i = 1,2,...n\)let\(X\)denote period that system functions properly. then for any nonnegative integer x

\(\begin{aligned}{c}{\rm P}\left( {X \ge x} \right) &= {\rm P}\left( {{X_1} \ge x,....,{X_n} \ge x.} \right)\\ &= {\rm P}\left( {{X_1} \ge x} \right)....{\rm P}\left( {{X_n} \ge x} \right)\end{aligned}\)

because the n components are independent

\({\rm P}\left( {{X_i} \ge x} \right) = {\left( {1 - {p_i}} \right)^x}\)

Therefore\({\rm P}\left( {X \ge x} \right) = \prod\limits_{i = 1}^n {{{\left( {1 - {p_i}} \right)}^x}} \)

It follows that

\(\begin{aligned}{c}{\rm P}\left( {X = x} \right) &= {\rm P}\left( {X \ge x} \right) - {\rm P}\left( {X \ge x + 1} \right)\\ &= \prod\limits_{i = 1}^n {{{\left( {1 - {p_i}} \right)}^x}} - \prod\limits_{i = 1}^n {{{\left( {1 - {p_i}} \right)}^{x + 1}}} \end{aligned}\)

Therefore

\({\rm P}\left( {X = x} \right) = \left( {1 - \prod\limits_{i = 1}^n {\left( {1 - {p_i}} \right)} } \right){\left( {\prod\limits_{i = 1}^n {\left( {1 - {p_i}} \right)} } \right)^x}\)

Hence it can be seen that this is the pf of the geometric distribution with

\(p = 1 - \prod\limits_{i = 1}^n {\left( {1 - {p_i}} \right)} \)

Therefore number of period for which the system will function properly will follow geometric distribution with \(p = 1 - \prod\limits_{i = 1}^n {\left( {1 - {p_i}} \right)} \)

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Most popular questions from this chapter

Suppose that on a certain examination in advanced mathematics, students from university A achieve scores normally distributed with a mean of 625 and a variance of 100, and students from university B achieve scores normally distributed with a mean of 600 and a variance of 150. If two students from university A and three students from university B take this examination, what is the probability that the average of the scores of the two students from university A will be greater than the average of the scores of the three students from university B? Hint: Determine the distribution of the difference between the two averages

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