Question

The equation${\left(x+1\right)}^2-5\left(x+1\right)+6=0$ is of ___ type. To solve the equation, we set W = ___ . The resulting quadratic equation is ___ .

Short answer

The equation${\left(x+1\right)}^2-5\left(x+1\right)+6=0$ is of quadratic type. To solve the equation, we set $W=\left(x+1\right)$. The resulting quadratic equation is$W^2-5W+6=0$

Step-by-step solution

Step 1. Apply the concept of quadratic equations.

A quadratic equation is an equation of the form$a{x}^2+bx+c=0$ where a, b, and c are real numbers with$a\ne 0$

Step 2. Analyze the given expression.

Given

${\left(x+1\right)}^2-5\left(x+1\right)+6=0$

This is a quadratic equation.

Step 3. Solve.

To solve the equation, we set$W=\left(x+1\right)$

The resulting equation is$W^2-5W+6=0$