Question

Factor the expression completely.

$16-4t^2$

Short answer

Factorized form of $16-4t^2$is$4\left(2-t\right)\left(2+t\right)$.

Step-by-step solution

Step 1. Take the common out of the expression.

$16-4t^2=4\left(4\right)-4\left(t^2\right)$

Step 2. Re write the expression after factorizing the expression.

$4\left(4\right)-4\left(t^2\right)=4\left(4-t^2\right)$

Here we may use the identity,

$\left(a^2-b^2\right)=\left(a-b\right)\left(a+b\right)$

Step 3. Factorized from of the expression is:

$\begin{array}{c}4\left(4-t^2\right)=4\left(2^2-t^2\right)\\ =4\left(2-t\right)\left(2+t\right)\end{array}$