Question

The functiongraphed below is defined by a polynomial expression of degree 4. Use the graph to solve the exercise.

The solutions of the equation $f\left(x\right)=0$are the ____intercepts of the graph of $f$. The solution of the inequality $f\left(x\right)\ge 0$is the set of $x$-values at which the graph of $f$is on or above the ____ -axis. From the graph of$f$we find that the solutions of the equation $f\left(x\right)=0$ are$x=\_\_\_\_$, and $x=\_\_\_\_$, and the solution of the inequality $f\left(x\right)\ge 0$is ____.

Short answer

Write the question by filling the gap given in step 1.

Step-by-step solution

Step 1. Filling all the gap.

$\begin{array}{l}x\\ x\\ 1\\ 7\\ \left(2,6\right)\end{array}$

 Step 2. Concept of solution of fx=0 and fx≥0.

The solution of the equation $f\left(x\right)=0$are the $x$- intercept of $f$and the solution of the inequality $f\left(x\right)\ge 0$is the set of $x$-values at which the graph of$f$ is on or above the $x$-axis.

Step 3. Determining the solution of fx=0 and fx≥0.

The function $f\left(x\right)=0$is at $x=1,7$and the solution of the inequality $f\left(x\right)\ge 0$ is $\left(2,6\right)$.