Question

the point (x, y) is on the terminal side of angle in standard position. Find the exact value of the given trigonometric function

$(6,-3),\tan \vartheta$

Short answer

$\tan \vartheta =\frac{-1}{2}$

Step-by-step solution

Step 1. Given information

$(6,-3),\tan \vartheta$

Step 2. Solving for tanϑ

We know that for any given point (x,y)

$\tan \vartheta =\frac{y}{x}$

Using this :

$$\begin{gathered} \tan \vartheta =\frac{y}{x} \\ \tan \vartheta =\frac{-3}{6} \\ \tan \vartheta =\frac{-1}{2} \end{gathered}$$