Question

In Problems $1-6$, solve each equation.

$\sqrt{3x+1}=4$.

Short answer

The solution for the equation$\sqrt{3x+1}=4$is,role="math" localid="1647072139921" $x=5$.

Step-by-step solution

Step 1 Given equation is,

$\sqrt{3x+1}=4$

Square the equation on both sides.

$$\begin{gathered} 3x+1={\left(4\right)}^2 \\ 3x+1=16 \end{gathered}$$

Step 2 Now simplify the obtained equation.

$$\begin{gathered} 3x+1=16 \\ 3x=16-1 \\ 3x=15 \\ x=\frac{15}{3} \\ x=5 \end{gathered}$$

The solution for the given equation is,$5$.