Question

In Problems $1-6$, solve each equation.

role="math" localid="1647069553838" $2x^2-x=0$.

Short answer

The solution set for the equation$2x^2-x=0$is, $\left\{0,\frac{1}{2}\right\}$.

Step-by-step solution

Step 1 Given equation is,

$2x^2-x=0$

First factor out the common terms.

role="math" localid="1647069944400" $2x^2-x=x\left(2x-1\right)$

Step 2 Now use the zero product property and simplify it.

$$\begin{gathered} x\left(2x-1\right)=0 \\ x=0and2x-1=0 \\ 2x=1 \\ x=\frac{1}{2} \end{gathered}$$

So, the required solution set is,$\left\{0,\frac{1}{2}\right\}$.