Question

Use graphing utility to approximate (round to two decimal places) the local maximum value and local minimum value of $f\left(x\right)=x^3-2x^2-4x+5$, for $-3<x<3$.

Short answer

The solution is the local maximum value is$6.48$at $x=-0.67$and local minimum value is$-3$at $x=2$

Step-by-step solution

Step 1. Given information 

Function:$f\left(x\right)=x^3-2x^2-4x+5$for$-3<x<3$

Step 2. Calculation  

Graph of the function $f\left(x\right)=x^3-2x^2-4x+5$for $-3<x<3$is -

So, the local maximum value is $6.48$at $x=-0.67$and local minimum value is$-3$at$x=2$.