Question

The intercepts of the equation$9x^2+4y=36$are ____________.

Short answer

The solution is$\left(-2,0\right),\left(2,0\right),\left(0,9\right)$.

Step-by-step solution

Step 1. Given information 

Equation:$9x^2+4y=36$

Step 2. Calculation  

Let $y=0$

$9x^2+4\left(0\right)=36$

$\frac{9x^2}{9}=\frac{36}{9}$

$\sqrt{x^2}=\sqrt{4}$

$x=\pm 2$

The x-intercepts are$-2$and $2$. Now let $x=0$

$9\left(0\right)+4y=36$

$\frac{4y}{4}=\frac{36}{4}$

$y=9$

The y-intercept is $9$.

Therefore, the intercepts of the equation $9x^2+4y=36$are$\left(-2,0\right),\left(2,0\right),\left(0,9\right)$.