Question

Find$\left|\left|v\right|\right|$
localid="1646775460766" $v=-2i+3j-3k$

Short answer

The norm of the vector $v=-2i+3j-3k$is$\left|\left|v\right|\right|=\sqrt{22}$

Step-by-step solution

Step 1. Give data 

Given vector is

$v=-2i+3j-3k$

Step 2. Norm of vector 

Use formula of the norm of a vector $v=ai+bj+ck$

$\left|\right|v\left|\right|=\sqrt{a^2+b^2+c^2}$

so norm of the vector $v=-2i+3j-3k$

localid="1646775530772" $$\begin{gathered} \left|\left|v\right|\right|=\sqrt{{\left(-2\right)}^2+{\left(3\right)}^2+{\left(-3\right)}^2} \\ \left|\left|v\right|\right|=\sqrt{4+9+9} \\ \left|\left|v\right|\right|=\sqrt{22} \end{gathered}$$