Question

Find an equation for the circle with a center at the point

$(0,1)$ and radius$3$. Graph this circle.

Short answer

Equation is$x^2+{(y-1)}^2=9$

Step-by-step solution

Step 1. The given information is

Centre at$(0,1)$and radius$3$

Step 2. Radius is r=(x-h)2+(y-k)2center is (h,k)=(0,1)

$$\begin{gathered} 3=\sqrt{{(x-0)}^2+{(y-1)}^2} \\ {3}^2=x^2+{(y-1)}^{2}9=x^2+{(y-1)}^2 \end{gathered}$$