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Chapter 9: Q. 14 (page 632)

In Problems 14–18, $P_{1} = (3 \sqrt{2}, 7 \sqrt{2})$ and $P_{2} = (8 \sqrt{2}, 2 \sqrt{2})$ .
Find the position vector $v$ equal to $\vec{P_{1} P_{2}}$ .

Short Answer

Expert verified

The answer is $<5 \sqrt{2}, - 5 \sqrt{2}>$

Step by step solution

Step 1. Given information

The points are

$P_{1} = (3 \sqrt{2}, 7 \sqrt{2}) P_{2} = (8 \sqrt{2}, 2 \sqrt{2})$

Step 2. Find the position vector v equal to P1P2→.

$v = <P_{2} - P_{1}> v = <(8 \sqrt{2} - 3 \sqrt{2}), (2 \sqrt{2} - 7 \sqrt{2})> v = <5 \sqrt{2}, - 5 \sqrt{2}>$

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Most popular questions from this chapter

An equation whose variables are polar coordinates is called a(n) ____ ______ .

In Problems55–66, the rectangular coordinates of a point are given. Find polar coordinates for each point.

$(0, 2)$

find the unit vector in the same direction as $v$

$v = - 3 j$

find each quantity if $v = 3 i - 5 j$ and $w = - 2 i + 3 j$

$||v + w||$

To test if the graph of a polar equation may be symmetric with respect to the line $θ = \frac{π}{2},$ replace $θ$ by ______.

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In Problems 14–18, $P_{1} = (3 \sqrt{2}, 7 \sqrt{2})$ and $P_{2} = (8 \sqrt{2}, 2 \sqrt{2})$ .
Find the position vector $v$ equal to $\vec{P_{1} P_{2}}$ .

Short Answer

Step by step solution

Step 1. Given information

Step 2. Find the position vector v equal to P1P2→.

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Most popular questions from this chapter

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In Problems 14–18, P1=32,72and P2=82,22.Find the position vector vequal toP1P2→.

Short Answer

Step by step solution

Step 1. Given information

Step 2. Find the position vector v equal to P1P2→.

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Most popular questions from this chapter

Recommended explanations on Math Textbooks

Discrete Mathematics

Applied Mathematics

Theoretical and Mathematical Physics

Geometry

Mechanics Maths

Statistics

Study anywhere. Anytime. Across all devices.

In Problems 14–18, $P_{1} = (3 \sqrt{2}, 7 \sqrt{2})$ and $P_{2} = (8 \sqrt{2}, 2 \sqrt{2})$ .
Find the position vector $v$ equal to $\vec{P_{1} P_{2}}$ .