Question

The $x$-coordinate of the vertex of $f\left(x\right)=a{x}^2+bx+c,a\ne 0$, is ________.

Short answer

The $x$-coordinate of the vertex of $f\left(x\right)=a{x}^2+bx+c,a\ne 0$, is $-\frac{b}{2a}$.

Step-by-step solution

Step 1. Given information.

The given statement is:

The $x$-coordinate of the vertex of $f\left(x\right)=a{x}^2+bx+c,a\ne 0$, is ________.

Step 2. Determine the missing term for the blank.

The vertex of a quadratic function $f\left(x\right)=a{x}^2+bx+c,a\ne 0$is:

$Vertex=\left(-\frac{b}{2a},f\left(-\frac{b}{2a}\right)\right)$

Step 3. Conclusion.

The $x$-coordinate of the vertex of $f\left(x\right)=a{x}^2+bx+c,a\ne 0$, is$-\frac{b}{2a}$.