Question

In Problems 56, list the intercepts and test for symmetry.

$y=x^2+4$

Short answer

The graph of the equation is symmetric with respect to the $y$-axis, the point of the equation $(0,4)$is a $y$-intercept and there is no $x$-intercept.

Step-by-step solution

Given information

The given equation is$y=x^2+4$.

Determine the x-intercept.

For $x$-intercept, substitute 0 for $y$and then solve for $x$.

$$\begin{gathered} 0=x^2+4 \\ x=\pm 2i \end{gathered}$$

Determine the y-intercept.

For $y$-intercept, substitute 0 for $x$and then solve for $y$.

$\begin{array}{rcl}y& =& 0^2+4\\ & =& 4\end{array}$

Determine the symmetry.

Substitute $y$for $-y$in the equation to check for symmetry with respect to $x$axis:

$\begin{array}{rcl}-y& =& x^2+4\\ y& =& -x^2-4\end{array}$

Notice that the right side of the equation after substitution is not equal to the right side of the initial equation.

Since the equations are not equivalent, the graph is not symmetric with respect to the $x$-axis.

Substitute $x$with $-x$in the equation to check for the symmetry with respect to $y$-axis:

$\begin{array}{rcl}y& =& {\left(-x\right)}^2+4\\ & =& x^2+4\end{array}$

Notice that the right side of the equation after substitution is equal to the right side of the initial equation.

Since the equations are equivalent, the equation is symmetric with respect to the $y$-axis.

Write the conclusion

There is no $x$-intercept.

The $y$-intercept is $\left(0,4\right)$.

The given equation is symmetric with respect to$y$axis.