Question

Find an equation for the line with the given properties. Express your answer using either the general form or the slope–intercept form of the equation of a line, whichever you prefer.

Slope $-\frac{2}{3}$, containing the point$(1,-1)$

Short answer

The equation of line is$2x+3y=-1$

Step-by-step solution

Step 1. Given Information 

The given slope of line is $-\frac{2}{3}$and containing the point$(1,-1)$

Step 2. Calculation

Substitute the given values in the general form of point slope equation of line.

$$\begin{gathered} y-y_1=m(x-x_1) \\ y-(-1)=(-\frac{2}{3})(x-1) \\ y+1=-\frac{2}{3}x+\frac{2}{3} \\ 3y+3=-2x+2 \\ 3y=-2x-1 \\ 2x+3y=-1 \end{gathered}$$