Question

Use a graphing utility to approximate the real solution of equation rounded to two decimal place . All solution lie between $-10$and $10$.

Equation is$2x^3-x^2-2x+1=0$.

Short answer

The root of the given equation are $\frac{1}{2},\pm 1$.The graph is shown below.

Step-by-step solution

Ste[p 1. Given information. 

Consider the given equation .$2x^3-x^2-2x+1=0$

Step 2. Find the root of the given equation. 

To find the root of the equation simplify the given equation.

$$\begin{gathered} x^2\left(2x-1\right)-1\left(2x-1\right) \\ \left(2x-1\right)=0,\left(x^2-1\right)=0 \\ x=\frac{1}{2},x=\pm 1 \end{gathered}$$

Step 3. Plot the graph.

The graph of the given equation using graphic utility as shown below.

Equation $2x^3-x^2-2x+1=0$.