Question

Graph the line containing the point P and having slope m.

$P(1,3),m=-\frac{2}{5}$

Short answer

The graph is

Step-by-step solution

Step 1. Given Information 

The given point is$P(1,3),m=-\frac{3}{4}$

Step 2. Explanation and Graph  

We know that slope is $-\frac{2}{5}$.

We will rewrite the slope as $\frac{-2}{5}$

Since, $m=\frac{rise}{run}$that is as numerator is negative so we will move 2 units down and then as denominator is positive so move 5 units right that is the other point will be $Q(6,1)$

Next, we can rewrite the slope as $\frac{2}{-5}$.

Since numerator is positive so we will move the point $P(1,3)$, 2 units up and as denominator is negative so we will move 5 units left that is the third point will be $R(-4,5)$

Draw a line passing through all the points.