Question

If the domain of a one-to-one function $f$is $\left[4,\infty \right]$, the range of its inverse, $f^{-1}$, is$\dots \dots$

Short answer

If the domain of a one-to-one function $f$is $\left[4,\infty \right]$, the range of of its inverse,$f^{-1}$is $\left[4,\infty \right]$

Step-by-step solution

Step 1. Definition

If$f$and$g$are inverse functions and $f$is one-to-function, the domain of$f$is the same as range of$g$.

Step 2. Explanation

Now given that domain of function$f$is$\left[4,\infty \right]$, then the range of its inverse$f^{-1}$is$\left[4,\infty \right]$