Question

find the remaining angle(s) and side(s) of each triangle, if it (they) exists. If no triangle exists, say “No triangle.”$a=2,b=3,c=1$

Short answer

No triangle

Step-by-step solution

Step 1.  Given information    

The given data is$a=2,b=3,c=1$

Step 2. Find the angle A 

Use cosines Rule, $\cos A=\frac{b^2+c^2-a^2}{2bc}$

Here, $a=2,b=3,c=1$

$$\begin{gathered} \cos A=\frac{3^2+1^2-2^2}{2.3.1} \\ \cos A=\frac{10-4}{6} \\ \cos A=1 \\ A=0 \end{gathered}$$

Step 3. Conclusion

One of the angle is 0, which is not possible.

So, the sides cannot form triangle