Question

The area K of a triangle with sides a, b, and c is K =_______ where s = ______.

Short answer

$K=\sqrt{s(s-a)(s-b)(s-c)}$

$s=\frac{1}{2}(a+b+c)$

Step-by-step solution

Given information

The area K of a triangle with sides a, b, and c is K =_______ where s = ______.

Answer

$$\begin{gathered} K=\sqrt{s(s-a)(s-b)(s-c)} \\ s=\frac{1}{2}(a+b+c) \end{gathered}$$