Question

Find$\tan \frac{\mathrm{\pi }}{4}=\_\_\_\_\_;\sin \frac{\mathrm{\pi }}{3}=\_\_\_\_\_$

Short answer

$$\begin{gathered} \tan \frac{\mathrm{\pi }}{4}=\mathbf{1} \\ \sin \frac{\mathrm{\pi }}{3}=\frac{\sqrt{\mathbf{3}}}{\mathbf{2}} \end{gathered}$$

Step-by-step solution

Step 1. Given information:

Given expression: $\tan \frac{\mathrm{\pi }}{4}=\_\_\_\_\_;\sin \frac{\mathrm{\pi }}{3}=\_\_\_\_\_$

We want to find value of given expression.

Step 2. Solution:

Using unit circle we have

$$\begin{gathered} \tan \frac{\mathrm{\pi }}{4}=\mathbf{1} \\ \sin \frac{\mathrm{\pi }}{3}=\frac{\sqrt{\mathbf{3}}}{\mathbf{2}} \end{gathered}$$