Question

In Problem, identify the graph of each equation without completing the squares.

$2y^2-3y+3x=0$

Short answer

The graph is of a parabola.

Step-by-step solution

Step 1. Given information

An equation is$2y^2-3y+3x=0$.

Step 2. Identify the graph.

Consider the equation: $2y^2-3y+3x=0$

The conic can be determined calculating the value of $B^2-4AC$.

$\begin{array}{rcl}{B}^2-4AC& =& {\left(0\right)}^2-4\left(0\right)\left(1\right)\\ & =& 0\end{array}$

The value of $B^2-4AC$is zero and therefore the given conic is a parabola.