Question

Use a graphing utility to find the indicated limit rounded to two decimal places.

$\underset{x\to -1}{\lim }\frac{x^3+2x^2+x}{x^4+x^3+2x+2}$

Short answer

The value of the limit rounded to two decimal places is$0.00$

Step-by-step solution

Step 1. Given information

The given limit is$\underset{x\to -1}{\lim }\frac{x^3+2x^2+x}{x^4+x^3+2x+2}$

Using a graphing utility we will find the table of values to find the value of the given limit.

Step 2. Table of values

The table of values is:

Therefore$\underset{x\to -1}{\lim }\frac{x^3+2x^2+x}{x^4+x^3+2x+2}=0.00$